481

我有一个包含 XML 的 Java 字符串,没有换行符或缩进。我想把它变成一个格式很好的 XML 的字符串。我该怎么做呢?

String unformattedXml = "<tag><nested>hello</nested></tag>";
String formattedXml = new [UnknownClass]().format(unformattedXml);

注意:我的输入是String。我的输出是一个String

(基本)模拟结果:

<?xml version="1.0" encoding="UTF-8"?>
<root>
  <tag>
    <nested>hello</nested>
  </tag>
</root>
4

34 回答 34

288
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "2");
// initialize StreamResult with File object to save to file
StreamResult result = new StreamResult(new StringWriter());
DOMSource source = new DOMSource(doc);
transformer.transform(source, result);
String xmlString = result.getWriter().toString();
System.out.println(xmlString);

注意:结果可能因 Java 版本而异。搜索特定于您的平台的解决方法。

于 2008-09-26T12:26:41.027 回答
138

这是我自己的问题的答案。我结合了各种结果的答案,编写了一个漂亮地打印 XML 的类。

不保证它如何响应无效的 XML 或大型文档。

package ecb.sdw.pretty;

import org.apache.xml.serialize.OutputFormat;
import org.apache.xml.serialize.XMLSerializer;
import org.w3c.dom.Document;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import java.io.IOException;
import java.io.StringReader;
import java.io.StringWriter;
import java.io.Writer;

/**
 * Pretty-prints xml, supplied as a string.
 * <p/>
 * eg.
 * <code>
 * String formattedXml = new XmlFormatter().format("<tag><nested>hello</nested></tag>");
 * </code>
 */
public class XmlFormatter {

    public XmlFormatter() {
    }

    public String format(String unformattedXml) {
        try {
            final Document document = parseXmlFile(unformattedXml);

            OutputFormat format = new OutputFormat(document);
            format.setLineWidth(65);
            format.setIndenting(true);
            format.setIndent(2);
            Writer out = new StringWriter();
            XMLSerializer serializer = new XMLSerializer(out, format);
            serializer.serialize(document);

            return out.toString();
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }

    private Document parseXmlFile(String in) {
        try {
            DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
            DocumentBuilder db = dbf.newDocumentBuilder();
            InputSource is = new InputSource(new StringReader(in));
            return db.parse(is);
        } catch (ParserConfigurationException e) {
            throw new RuntimeException(e);
        } catch (SAXException e) {
            throw new RuntimeException(e);
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }

    public static void main(String[] args) {
        String unformattedXml =
                "<?xml version=\"1.0\" encoding=\"UTF-8\"?><QueryMessage\n" +
                        "        xmlns=\"http://www.SDMX.org/resources/SDMXML/schemas/v2_0/message\"\n" +
                        "        xmlns:query=\"http://www.SDMX.org/resources/SDMXML/schemas/v2_0/query\">\n" +
                        "    <Query>\n" +
                        "        <query:CategorySchemeWhere>\n" +
                        "   \t\t\t\t\t         <query:AgencyID>ECB\n\n\n\n</query:AgencyID>\n" +
                        "        </query:CategorySchemeWhere>\n" +
                        "    </Query>\n\n\n\n\n" +
                        "</QueryMessage>";

        System.out.println(new XmlFormatter().format(unformattedXml));
    }

}
于 2008-09-26T13:13:15.330 回答
138

基于此答案的更简单的解决方案

public static String prettyFormat(String input, int indent) {
    try {
        Source xmlInput = new StreamSource(new StringReader(input));
        StringWriter stringWriter = new StringWriter();
        StreamResult xmlOutput = new StreamResult(stringWriter);
        TransformerFactory transformerFactory = TransformerFactory.newInstance();
        transformerFactory.setAttribute("indent-number", indent);
        transformerFactory.setAttribute(XMLConstants.ACCESS_EXTERNAL_DTD, "");
        transformerFactory.setAttribute(XMLConstants.ACCESS_EXTERNAL_STYLESHEET, "");
        Transformer transformer = transformerFactory.newTransformer(); 
        transformer.setOutputProperty(OutputKeys.INDENT, "yes");
        transformer.transform(xmlInput, xmlOutput);
        return xmlOutput.getWriter().toString();
    } catch (Exception e) {
        throw new RuntimeException(e); // simple exception handling, please review it
    }
}

public static String prettyFormat(String input) {
    return prettyFormat(input, 2);
}

测试用例:

prettyFormat("<root><child>aaa</child><child/></root>");

返回:

<?xml version="1.0" encoding="UTF-8"?>
<root>
  <child>aaa</child>
  <child/>
</root>

//忽略:原始编辑只需要在代码中的类名中缺少s。添加了多余的六个字符以在 SO 上获得超过 6 个字符的验证

于 2009-08-12T08:22:57.870 回答
105

现在是 2012 年,Java 可以比以前使用 XML 做更多的事情,我想为我接受的答案添加一个替代方案。这在 Java 6 之外没有依赖关系。

import org.w3c.dom.Node;
import org.w3c.dom.bootstrap.DOMImplementationRegistry;
import org.w3c.dom.ls.DOMImplementationLS;
import org.w3c.dom.ls.LSSerializer;
import org.xml.sax.InputSource;

import javax.xml.parsers.DocumentBuilderFactory;
import java.io.StringReader;

/**
 * Pretty-prints xml, supplied as a string.
 * <p/>
 * eg.
 * <code>
 * String formattedXml = new XmlFormatter().format("<tag><nested>hello</nested></tag>");
 * </code>
 */
public class XmlFormatter {

    public String format(String xml) {

        try {
            final InputSource src = new InputSource(new StringReader(xml));
            final Node document = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(src).getDocumentElement();
            final Boolean keepDeclaration = Boolean.valueOf(xml.startsWith("<?xml"));

        //May need this: System.setProperty(DOMImplementationRegistry.PROPERTY,"com.sun.org.apache.xerces.internal.dom.DOMImplementationSourceImpl");


            final DOMImplementationRegistry registry = DOMImplementationRegistry.newInstance();
            final DOMImplementationLS impl = (DOMImplementationLS) registry.getDOMImplementation("LS");
            final LSSerializer writer = impl.createLSSerializer();

            writer.getDomConfig().setParameter("format-pretty-print", Boolean.TRUE); // Set this to true if the output needs to be beautified.
            writer.getDomConfig().setParameter("xml-declaration", keepDeclaration); // Set this to true if the declaration is needed to be outputted.

            return writer.writeToString(document);
        } catch (Exception e) {
            throw new RuntimeException(e);
        }
    }

    public static void main(String[] args) {
        String unformattedXml =
                "<?xml version=\"1.0\" encoding=\"UTF-8\"?><QueryMessage\n" +
                        "        xmlns=\"http://www.SDMX.org/resources/SDMXML/schemas/v2_0/message\"\n" +
                        "        xmlns:query=\"http://www.SDMX.org/resources/SDMXML/schemas/v2_0/query\">\n" +
                        "    <Query>\n" +
                        "        <query:CategorySchemeWhere>\n" +
                        "   \t\t\t\t\t         <query:AgencyID>ECB\n\n\n\n</query:AgencyID>\n" +
                        "        </query:CategorySchemeWhere>\n" +
                        "    </Query>\n\n\n\n\n" +
                        "</QueryMessage>";

        System.out.println(new XmlFormatter().format(unformattedXml));
    }
}
于 2012-07-17T09:29:18.570 回答
54

请注意,评分最高的答案需要使用 xerces。

如果您不想添加此外部依赖项,则可以简单地使用标准 jdk 库(实际上是在内部使用 xerces 构建的)。

注意 jdk 1.5 版有一个错误,请参阅http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=6296446但现在已解决。

(注意如果发生错误,这将返回原始文本)

package com.test;

import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;

import javax.xml.transform.OutputKeys;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.sax.SAXSource;
import javax.xml.transform.sax.SAXTransformerFactory;
import javax.xml.transform.stream.StreamResult;

import org.xml.sax.InputSource;

public class XmlTest {
    public static void main(String[] args) {
        XmlTest t = new XmlTest();
        System.out.println(t.formatXml("<a><b><c/><d>text D</d><e value='0'/></b></a>"));
    }

    public String formatXml(String xml){
        try{
            Transformer serializer= SAXTransformerFactory.newInstance().newTransformer();
            serializer.setOutputProperty(OutputKeys.INDENT, "yes");
            //serializer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
            serializer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "2");
            //serializer.setOutputProperty("{http://xml.customer.org/xslt}indent-amount", "2");
            Source xmlSource=new SAXSource(new InputSource(new ByteArrayInputStream(xml.getBytes())));
            StreamResult res =  new StreamResult(new ByteArrayOutputStream());            
            serializer.transform(xmlSource, res);
            return new String(((ByteArrayOutputStream)res.getOutputStream()).toByteArray());
        }catch(Exception e){
            //TODO log error
            return xml;
        }
    }

}
于 2010-12-17T16:27:31.120 回答
33

我过去使用org.dom4j.io.OutputFormat.createPrettyPrint()方法打印得很漂亮

public String prettyPrint(final String xml){  

    if (StringUtils.isBlank(xml)) {
        throw new RuntimeException("xml was null or blank in prettyPrint()");
    }

    final StringWriter sw;

    try {
        final OutputFormat format = OutputFormat.createPrettyPrint();
        final org.dom4j.Document document = DocumentHelper.parseText(xml);
        sw = new StringWriter();
        final XMLWriter writer = new XMLWriter(sw, format);
        writer.write(document);
    }
    catch (Exception e) {
        throw new RuntimeException("Error pretty printing xml:\n" + xml, e);
    }
    return sw.toString();
}
于 2008-11-03T23:22:37.973 回答
19

这是使用dom4j的一种方法:

进口:

import org.dom4j.Document;  
import org.dom4j.DocumentHelper;  
import org.dom4j.io.OutputFormat;  
import org.dom4j.io.XMLWriter;

代码:

String xml = "<your xml='here'/>";  
Document doc = DocumentHelper.parseText(xml);  
StringWriter sw = new StringWriter();  
OutputFormat format = OutputFormat.createPrettyPrint();  
XMLWriter xw = new XMLWriter(sw, format);  
xw.write(doc);  
String result = sw.toString();
于 2010-04-08T10:29:00.610 回答
17

由于String您是DOM从. 但是,如果您知道您的 XML 字符串是有效的,并且您不想产生将字符串解析为 DOM 的内存开销,那么在 DOM 上运行转换以获取字符串 - 您可以做一些老式的逐个字符解析。在每个字符后插入一个换行符和空格,保留并缩进计数器(以确定空格数),为每个字符递增,为每个看到的字符递减。NodeTransformer</...><...></...>

免责声明 - 我对以下函数进行了剪切/粘贴/文本编辑,因此它们可能无法按原样编译。

public static final Element createDOM(String strXML) 
    throws ParserConfigurationException, SAXException, IOException {

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    dbf.setValidating(true);
    DocumentBuilder db = dbf.newDocumentBuilder();
    InputSource sourceXML = new InputSource(new StringReader(strXML));
    Document xmlDoc = db.parse(sourceXML);
    Element e = xmlDoc.getDocumentElement();
    e.normalize();
    return e;
}

public static final void prettyPrint(Node xml, OutputStream out)
    throws TransformerConfigurationException, TransformerFactoryConfigurationError, TransformerException {
    Transformer tf = TransformerFactory.newInstance().newTransformer();
    tf.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
    tf.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
    tf.setOutputProperty(OutputKeys.INDENT, "yes");
    tf.transform(new DOMSource(xml), new StreamResult(out));
}
于 2008-09-26T12:58:23.230 回答
15

Kevin Hakanson 说:“但是,如果您知道您的 XML 字符串是有效的,并且您不想招致将字符串解析为 DOM 的内存开销,然后在 DOM 上运行转换以获取字符串 - 您可以只需逐个字符解析一些老式字符。在每个字符后插入换行符和空格,保留并缩进计数器(以确定空格数),为每个 <...> 增加并为每个看到的减少。

同意。这种方法要快得多,并且依赖性要少得多。

示例解决方案:

/**
 * XML utils, including formatting.
 */
public class XmlUtils
{
  private static XmlFormatter formatter = new XmlFormatter(2, 80);

  public static String formatXml(String s)
  {
    return formatter.format(s, 0);
  }

  public static String formatXml(String s, int initialIndent)
  {
    return formatter.format(s, initialIndent);
  }

  private static class XmlFormatter
  {
    private int indentNumChars;
    private int lineLength;
    private boolean singleLine;

    public XmlFormatter(int indentNumChars, int lineLength)
    {
      this.indentNumChars = indentNumChars;
      this.lineLength = lineLength;
    }

    public synchronized String format(String s, int initialIndent)
    {
      int indent = initialIndent;
      StringBuilder sb = new StringBuilder();
      for (int i = 0; i < s.length(); i++)
      {
        char currentChar = s.charAt(i);
        if (currentChar == '<')
        {
          char nextChar = s.charAt(i + 1);
          if (nextChar == '/')
            indent -= indentNumChars;
          if (!singleLine)   // Don't indent before closing element if we're creating opening and closing elements on a single line.
            sb.append(buildWhitespace(indent));
          if (nextChar != '?' && nextChar != '!' && nextChar != '/')
            indent += indentNumChars;
          singleLine = false;  // Reset flag.
        }
        sb.append(currentChar);
        if (currentChar == '>')
        {
          if (s.charAt(i - 1) == '/')
          {
            indent -= indentNumChars;
            sb.append("\n");
          }
          else
          {
            int nextStartElementPos = s.indexOf('<', i);
            if (nextStartElementPos > i + 1)
            {
              String textBetweenElements = s.substring(i + 1, nextStartElementPos);

              // If the space between elements is solely newlines, let them through to preserve additional newlines in source document.
              if (textBetweenElements.replaceAll("\n", "").length() == 0)
              {
                sb.append(textBetweenElements + "\n");
              }
              // Put tags and text on a single line if the text is short.
              else if (textBetweenElements.length() <= lineLength * 0.5)
              {
                sb.append(textBetweenElements);
                singleLine = true;
              }
              // For larger amounts of text, wrap lines to a maximum line length.
              else
              {
                sb.append("\n" + lineWrap(textBetweenElements, lineLength, indent, null) + "\n");
              }
              i = nextStartElementPos - 1;
            }
            else
            {
              sb.append("\n");
            }
          }
        }
      }
      return sb.toString();
    }
  }

  private static String buildWhitespace(int numChars)
  {
    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < numChars; i++)
      sb.append(" ");
    return sb.toString();
  }

  /**
   * Wraps the supplied text to the specified line length.
   * @lineLength the maximum length of each line in the returned string (not including indent if specified).
   * @indent optional number of whitespace characters to prepend to each line before the text.
   * @linePrefix optional string to append to the indent (before the text).
   * @returns the supplied text wrapped so that no line exceeds the specified line length + indent, optionally with
   * indent and prefix applied to each line.
   */
  private static String lineWrap(String s, int lineLength, Integer indent, String linePrefix)
  {
    if (s == null)
      return null;

    StringBuilder sb = new StringBuilder();
    int lineStartPos = 0;
    int lineEndPos;
    boolean firstLine = true;
    while(lineStartPos < s.length())
    {
      if (!firstLine)
        sb.append("\n");
      else
        firstLine = false;

      if (lineStartPos + lineLength > s.length())
        lineEndPos = s.length() - 1;
      else
      {
        lineEndPos = lineStartPos + lineLength - 1;
        while (lineEndPos > lineStartPos && (s.charAt(lineEndPos) != ' ' && s.charAt(lineEndPos) != '\t'))
          lineEndPos--;
      }
      sb.append(buildWhitespace(indent));
      if (linePrefix != null)
        sb.append(linePrefix);

      sb.append(s.substring(lineStartPos, lineEndPos + 1));
      lineStartPos = lineEndPos + 1;
    }
    return sb.toString();
  }

  // other utils removed for brevity
}
于 2010-05-27T10:50:22.450 回答
12

如果可以使用 3rd 方 XML 库,那么您可以使用比当前投票率最高的 答案建议 的要简单得多的东西。

据说输入和输出都应该是字符串,所以这是一个使用XOM库实现的实用方法:

import nu.xom.*;
import java.io.*;

[...]

public static String format(String xml) throws ParsingException, IOException {
    ByteArrayOutputStream out = new ByteArrayOutputStream();
    Serializer serializer = new Serializer(out);
    serializer.setIndent(4);  // or whatever you like
    serializer.write(new Builder().build(xml, ""));
    return out.toString("UTF-8");
}

我测试了它是否有效,结果取决于您的 JRE 版本或类似的东西。要了解如何根据自己的喜好自定义输出格式,请查看SerializerAPI。

这实际上比我想象的要长 - 需要一些额外的行,因为Serializer想要OutputStream写入。但请注意,这里几乎没有用于实际操作 XML 的代码。

(这个答案是我对 XOM 的评估的一部分,在我关于替换 dom4j 的最佳 Java XML 库的问题中,它被建议作为一个选项。作为记录,使用 dom4j,您可以使用和类似轻松地实现这一点。编辑:.. .如mlo55的回答所示。)XMLWriterOutputFormat

于 2009-06-07T16:26:27.947 回答
11

嗯......遇到了这样的事情,这是一个已知的错误......只需添加这个 OutputProperty ..

transformer.setOutputProperty(OutputPropertiesFactory.S_KEY_INDENT_AMOUNT, "8");

希望这可以帮助 ...

于 2009-12-22T19:26:31.643 回答
10

关于“您必须首先构建 DOM 树”的评论:不,您不需要也不应该这样做。

相反,创建一个 StreamSource (new StreamSource(new StringReader(str)),并将其提供给提到的身份转换器。这将使用 SAX 解析器,结果会更快。在这种情况下,构建中间树纯粹是开销。否则排名靠前的答案是好的。

于 2009-02-26T19:54:53.660 回答
9

使用斯卡拉:

import xml._
val xml = XML.loadString("<tag><nested>hello</nested></tag>")
val formatted = new PrettyPrinter(150, 2).format(xml)
println(formatted)

如果您依赖 scala-library.jar,您也可以在 Java 中执行此操作。它看起来像这样:

import scala.xml.*;

public class FormatXML {
    public static void main(String[] args) {
        String unformattedXml = "<tag><nested>hello</nested></tag>";
        PrettyPrinter pp = new PrettyPrinter(150, 3);
        String formatted = pp.format(XML.loadString(unformattedXml), TopScope$.MODULE$);
        System.out.println(formatted);
    }
}

PrettyPrinter对象由两个整数构成,第一个是最大行长,第二个是缩进步骤。

于 2011-03-08T01:58:41.720 回答
9

来自milosmns的略微改进的版本......

public static String getPrettyXml(String xml) {
    if (xml == null || xml.trim().length() == 0) return "";

    int stack = 0;
    StringBuilder pretty = new StringBuilder();
    String[] rows = xml.trim().replaceAll(">", ">\n").replaceAll("<", "\n<").split("\n");

    for (int i = 0; i < rows.length; i++) {
        if (rows[i] == null || rows[i].trim().length() == 0) continue;

        String row = rows[i].trim();
        if (row.startsWith("<?")) {
            pretty.append(row + "\n");
        } else if (row.startsWith("</")) {
            String indent = repeatString(--stack);
            pretty.append(indent + row + "\n");
        } else if (row.startsWith("<") && row.endsWith("/>") == false) {
            String indent = repeatString(stack++);
            pretty.append(indent + row + "\n");
            if (row.endsWith("]]>")) stack--;
        } else {
            String indent = repeatString(stack);
            pretty.append(indent + row + "\n");
        }
    }

    return pretty.toString().trim();
}

private static String repeatString(int stack) {
     StringBuilder indent = new StringBuilder();
     for (int i = 0; i < stack; i++) {
        indent.append(" ");
     }
     return indent.toString();
} 
于 2014-07-09T10:17:46.987 回答
8

仅供将来参考,这是一个对我有用的解决方案(感谢@George Hawkins 在其中一个答案中发布的评论):

DOMImplementationRegistry registry = DOMImplementationRegistry.newInstance();
DOMImplementationLS impl = (DOMImplementationLS) registry.getDOMImplementation("LS");
LSSerializer writer = impl.createLSSerializer();
writer.getDomConfig().setParameter("format-pretty-print", Boolean.TRUE);
LSOutput output = impl.createLSOutput();
ByteArrayOutputStream out = new ByteArrayOutputStream();
output.setByteStream(out);
writer.write(document, output);
String xmlStr = new String(out.toByteArray());
于 2011-10-10T14:43:05.040 回答
6

以上所有解决方案都对我不起作用,然后我发现了这个http://myshittycode.com/2014/02/10/java-properly-indenting-xml-string/

线索是使用 XPath 删除空格

    String xml = "<root>" +
             "\n   " +
             "\n<name>Coco Puff</name>" +
             "\n        <total>10</total>    </root>";

try {
    Document document = DocumentBuilderFactory.newInstance()
            .newDocumentBuilder()
            .parse(new InputSource(new ByteArrayInputStream(xml.getBytes("utf-8"))));

    XPath xPath = XPathFactory.newInstance().newXPath();
    NodeList nodeList = (NodeList) xPath.evaluate("//text()[normalize-space()='']",
                                                  document,
                                                  XPathConstants.NODESET);

    for (int i = 0; i < nodeList.getLength(); ++i) {
        Node node = nodeList.item(i);
        node.getParentNode().removeChild(node);
    }

    Transformer transformer = TransformerFactory.newInstance().newTransformer();
    transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
    transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
    transformer.setOutputProperty(OutputKeys.INDENT, "yes");
    transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");

    StringWriter stringWriter = new StringWriter();
    StreamResult streamResult = new StreamResult(stringWriter);

    transformer.transform(new DOMSource(document), streamResult);

    System.out.println(stringWriter.toString());
}
catch (Exception e) {
    e.printStackTrace();
}
于 2015-05-13T11:27:01.927 回答
6

下面的代码完美运行

import javax.xml.transform.OutputKeys;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

String formattedXml1 = prettyFormat("<root><child>aaa</child><child/></root>");

public static String prettyFormat(String input) {
    return prettyFormat(input, "2");
}

public static String prettyFormat(String input, String indent) {
    Source xmlInput = new StreamSource(new StringReader(input));
    StringWriter stringWriter = new StringWriter();
    try {
        TransformerFactory transformerFactory = TransformerFactory.newInstance();
        Transformer transformer = transformerFactory.newTransformer();
        transformer.setOutputProperty(OutputKeys.INDENT, "yes");
        transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", indent);
        transformer.transform(xmlInput, new StreamResult(stringWriter));

        String pretty = stringWriter.toString();
        pretty = pretty.replace("\r\n", "\n");
        return pretty;              
    } catch (Exception e) {
        throw new RuntimeException(e);
    }
}
于 2016-06-02T18:31:39.430 回答
6

我混合所有这些并编写一个小程序。它正在从 xml 文件中读取并打印出来。只是代替 xzy 给你的文件路径。

    public static void main(String[] args) throws Exception {
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    dbf.setValidating(false);
    DocumentBuilder db = dbf.newDocumentBuilder();
    Document doc = db.parse(new FileInputStream(new File("C:/Users/xyz.xml")));
    prettyPrint(doc);

}

private static String prettyPrint(Document document)
        throws TransformerException {
    TransformerFactory transformerFactory = TransformerFactory
            .newInstance();
    Transformer transformer = transformerFactory.newTransformer();
    transformer.setOutputProperty(OutputKeys.INDENT, "yes");
    transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "2");
    transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
    transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "no");
    DOMSource source = new DOMSource(document);
    StringWriter strWriter = new StringWriter();
    StreamResult result = new StreamResult(strWriter);transformer.transform(source, result);
    System.out.println(strWriter.getBuffer().toString());

    return strWriter.getBuffer().toString();

}
于 2018-07-10T19:47:32.813 回答
5

如果您确定您有一个有效的 XML,那么这个很简单,并且避免了 XML DOM 树。也许有一些错误,如果您看到任何内容,请发表评论

public String prettyPrint(String xml) {
            if (xml == null || xml.trim().length() == 0) return "";

            int stack = 0;
            StringBuilder pretty = new StringBuilder();
            String[] rows = xml.trim().replaceAll(">", ">\n").replaceAll("<", "\n<").split("\n");

            for (int i = 0; i < rows.length; i++) {
                    if (rows[i] == null || rows[i].trim().length() == 0) continue;

                    String row = rows[i].trim();
                    if (row.startsWith("<?")) {
                            // xml version tag
                            pretty.append(row + "\n");
                    } else if (row.startsWith("</")) {
                            // closing tag
                            String indent = repeatString("    ", --stack);
                            pretty.append(indent + row + "\n");
                    } else if (row.startsWith("<")) {
                            // starting tag
                            String indent = repeatString("    ", stack++);
                            pretty.append(indent + row + "\n");
                    } else {
                            // tag data
                            String indent = repeatString("    ", stack);
                            pretty.append(indent + row + "\n");
                    }
            }

            return pretty.toString().trim();
    }
于 2014-02-12T18:16:24.437 回答
5

对我们有用的另一种解决方案

import java.io.StringWriter;
import org.dom4j.DocumentHelper;
import org.dom4j.io.OutputFormat;
import org.dom4j.io.XMLWriter;

**
 * Pretty Print XML String
 * 
 * @param inputXmlString
 * @return
 */
public static String prettyPrintXml(String xml) {

    final StringWriter sw;

    try {
        final OutputFormat format = OutputFormat.createPrettyPrint();
        final org.dom4j.Document document = DocumentHelper.parseText(xml);
        sw = new StringWriter();
        final XMLWriter writer = new XMLWriter(sw, format);
        writer.write(document);
    }
    catch (Exception e) {
        throw new RuntimeException("Error pretty printing xml:\n" + xml, e);
    }
    return sw.toString();
}
于 2015-07-22T18:45:00.773 回答
4

使用 jdom2: http: //www.jdom.org/

import java.io.StringReader;
import org.jdom2.input.SAXBuilder;
import org.jdom2.output.Format;
import org.jdom2.output.XMLOutputter;

String prettyXml = new XMLOutputter(Format.getPrettyFormat()).
                         outputString(new SAXBuilder().build(new StringReader(uglyXml)));
于 2015-05-11T15:00:47.757 回答
3

作为maxcodeskrapsDavid Easleymilosmns答案的替代方案,请查看我的轻量级、高性能漂亮打印机库:xml-formatter

// construct lightweight, threadsafe, instance
PrettyPrinter prettyPrinter = PrettyPrinterBuilder.newPrettyPrinter().build();

StringBuilder buffer = new StringBuilder();
String xml = ..; // also works with char[] or Reader

if(prettyPrinter.process(xml, buffer)) {
     // valid XML, print buffer
} else {
     // invalid XML, print xml
}

有时,就像直接从文件运行模拟的 SOAP 服务时,最好有一个漂亮的打印机,它也可以处理已经漂亮打印的 XML:

PrettyPrinter prettyPrinter = PrettyPrinterBuilder.newPrettyPrinter().ignoreWhitespace().build();

正如一些人评论的那样,漂亮的打印只是以更易于阅读的形式呈现 XML 的一种方式 - 空格严格不属于您的 XML 数据。

该库旨在用于日志记录的漂亮打印,还包括用于过滤(子树删除/匿名化)和在 CDATA 和文本节点中漂亮打印 XML 的功能。

于 2014-12-28T22:25:09.383 回答
2

我有同样的问题,我在 JTidy 上取得了巨大的成功(http://jtidy.sourceforge.net/index.html

例子:

Tidy t = new Tidy();
t.setIndentContent(true);
Document d = t.parseDOM(
    new ByteArrayInputStream("HTML goes here", null);

OutputStream out = new ByteArrayOutputStream();
t.pprint(d, out);
String html = out.toString();
于 2010-06-11T20:30:15.983 回答
2

对于那些寻找快速而肮脏的解决方案的人 - 不需要 XML 100% 有效。例如,在 REST / SOAP 日志记录的情况下(你永远不知道其他人发送了什么;-))

我发现并改进了我在网上找到的代码片段,我认为这里仍然缺少它作为一种有效的可能方法:

public static String prettyPrintXMLAsString(String xmlString) {
    /* Remove new lines */
    final String LINE_BREAK = "\n";
    xmlString = xmlString.replaceAll(LINE_BREAK, "");
    StringBuffer prettyPrintXml = new StringBuffer();
    /* Group the xml tags */
    Pattern pattern = Pattern.compile("(<[^/][^>]+>)?([^<]*)(</[^>]+>)?(<[^/][^>]+/>)?");
    Matcher matcher = pattern.matcher(xmlString);
    int tabCount = 0;
    while (matcher.find()) {
        String str1 = (null == matcher.group(1) || "null".equals(matcher.group())) ? "" : matcher.group(1);
        String str2 = (null == matcher.group(2) || "null".equals(matcher.group())) ? "" : matcher.group(2);
        String str3 = (null == matcher.group(3) || "null".equals(matcher.group())) ? "" : matcher.group(3);
        String str4 = (null == matcher.group(4) || "null".equals(matcher.group())) ? "" : matcher.group(4);

        if (matcher.group() != null && !matcher.group().trim().equals("")) {
            printTabs(tabCount, prettyPrintXml);
            if (!str1.equals("") && str3.equals("")) {
                ++tabCount;
            }
            if (str1.equals("") && !str3.equals("")) {
                --tabCount;
                prettyPrintXml.deleteCharAt(prettyPrintXml.length() - 1);
            }

            prettyPrintXml.append(str1);
            prettyPrintXml.append(str2);
            prettyPrintXml.append(str3);
            if (!str4.equals("")) {
                prettyPrintXml.append(LINE_BREAK);
                printTabs(tabCount, prettyPrintXml);
                prettyPrintXml.append(str4);
            }
            prettyPrintXml.append(LINE_BREAK);
        }
    }
    return prettyPrintXml.toString();
}

private static void printTabs(int count, StringBuffer stringBuffer) {
    for (int i = 0; i < count; i++) {
        stringBuffer.append("\t");
    }
}

public static void main(String[] args) {
    String x = new String(
            "<soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\"><soap:Body><soap:Fault><faultcode>soap:Client</faultcode><faultstring>INVALID_MESSAGE</faultstring><detail><ns3:XcbSoapFault xmlns=\"\" xmlns:ns3=\"http://www.someapp.eu/xcb/types/xcb/v1\"><CauseCode>20007</CauseCode><CauseText>INVALID_MESSAGE</CauseText><DebugInfo>Problems creating SAAJ object model</DebugInfo></ns3:XcbSoapFault></detail></soap:Fault></soap:Body></soap:Envelope>");
    System.out.println(prettyPrintXMLAsString(x));
}

这是输出:

<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  <soap:Body>
    <soap:Fault>
        <faultcode>soap:Client</faultcode>
        <faultstring>INVALID_MESSAGE</faultstring>
        <detail>
            <ns3:XcbSoapFault xmlns="" xmlns:ns3="http://www.someapp.eu/xcb/types/xcb/v1">
                <CauseCode>20007</CauseCode>
                <CauseText>INVALID_MESSAGE</CauseText>
                <DebugInfo>Problems creating SAAJ object model</DebugInfo>
            </ns3:XcbSoapFault>
        </detail>
    </soap:Fault>
  </soap:Body>
</soap:Envelope>
于 2013-10-07T23:32:49.133 回答
2

我总是使用以下功能:

public static String prettyPrintXml(String xmlStringToBeFormatted) {
    String formattedXmlString = null;
    try {
        DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
        documentBuilderFactory.setValidating(true);
        DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
        InputSource inputSource = new InputSource(new StringReader(xmlStringToBeFormatted));
        Document document = documentBuilder.parse(inputSource);

        Transformer transformer = TransformerFactory.newInstance().newTransformer();
        transformer.setOutputProperty(OutputKeys.INDENT, "yes");
        transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "2");

        StreamResult streamResult = new StreamResult(new StringWriter());
        DOMSource dOMSource = new DOMSource(document);
        transformer.transform(dOMSource, streamResult);
        formattedXmlString = streamResult.getWriter().toString().trim();
    } catch (Exception ex) {
        StringWriter sw = new StringWriter();
        ex.printStackTrace(new PrintWriter(sw));
        System.err.println(sw.toString());
    }
    return formattedXmlString;
}
于 2019-05-06T13:27:58.873 回答
1

有一个非常好的命令行 XML 实用程序,称为 xmlstarlet( http://xmlstar.sourceforge.net/ ),它可以做很多人使用的很多事情。

您可以使用 Runtime.exec 以编程方式执行该程序,然后读入格式化的输出文件。它具有比几行 Java 代码所能提供的更多选项和更好的错误报告。

下载 xmlstarlet: http: //sourceforge.net/project/showfiles.php ?group_id=66612&package_id=64589

于 2008-09-26T14:38:17.920 回答
1

我发现在 Java 1.6.0_32 中,漂亮打印 XML字符串的常规方法(使用带有 null 或标识 xslt 的 Transformer)的行为不像我想要的那样,如果标签仅由空格分隔,而不是没有分隔文本。我尝试<xsl:strip-space elements="*"/>在我的模板中使用无济于事。我发现的最简单的解决方案是使用 SAXSource 和 XML 过滤器以我想要的方式剥离空间。由于我的解决方案是用于日志记录,因此我还将其扩展为处理不完整的 XML 片段。请注意,如果您使用 DOMSource,正常方法似乎可以正常工作,但由于不完整和内存开销,我不想使用它。

public static class WhitespaceIgnoreFilter extends XMLFilterImpl
{

    @Override
    public void ignorableWhitespace(char[] arg0,
                                    int arg1,
                                    int arg2) throws SAXException
    {
        //Ignore it then...
    }

    @Override
    public void characters( char[] ch,
                            int start,
                            int length) throws SAXException
    {
        if (!new String(ch, start, length).trim().equals("")) 
               super.characters(ch, start, length); 
    }
}

public static String prettyXML(String logMsg, boolean allowBadlyFormedFragments) throws SAXException, IOException, TransformerException
    {
        TransformerFactory transFactory = TransformerFactory.newInstance();
        transFactory.setAttribute("indent-number", new Integer(2));
        Transformer transformer = transFactory.newTransformer();
        transformer.setOutputProperty(OutputKeys.INDENT, "yes");
        transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
        StringWriter out = new StringWriter();
        XMLReader masterParser = SAXHelper.getSAXParser(true);
        XMLFilter parser = new WhitespaceIgnoreFilter();
        parser.setParent(masterParser);

        if(allowBadlyFormedFragments)
        {
            transformer.setErrorListener(new ErrorListener()
            {
                @Override
                public void warning(TransformerException exception) throws TransformerException
                {
                }

                @Override
                public void fatalError(TransformerException exception) throws TransformerException
                {
                }

                @Override
                public void error(TransformerException exception) throws TransformerException
                {
                }
            });
        }

        try
        {
            transformer.transform(new SAXSource(parser, new InputSource(new StringReader(logMsg))), new StreamResult(out));
        }
        catch (TransformerException e)
        {
            if(e.getCause() != null && e.getCause() instanceof SAXParseException)
            {
                if(!allowBadlyFormedFragments || !"XML document structures must start and end within the same entity.".equals(e.getCause().getMessage()))
                {
                    throw e;
                }
            }
            else
            {
                throw e;
            }
        }
        out.flush();
        return out.toString();
    }
于 2012-07-05T19:36:29.060 回答
1

如果代码已经格式化,我在这里找到的 Java 1.6+ 解决方案不会重新格式化代码。对我有用的一个(并重新格式化了已经格式化的代码)如下。

import org.apache.xml.security.c14n.CanonicalizationException;
import org.apache.xml.security.c14n.Canonicalizer;
import org.apache.xml.security.c14n.InvalidCanonicalizerException;
import org.w3c.dom.Element;
import org.w3c.dom.bootstrap.DOMImplementationRegistry;
import org.w3c.dom.ls.DOMImplementationLS;
import org.w3c.dom.ls.LSSerializer;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.TransformerException;
import java.io.IOException;
import java.io.StringReader;

public class XmlUtils {
    public static String toCanonicalXml(String xml) throws InvalidCanonicalizerException, ParserConfigurationException, SAXException, CanonicalizationException, IOException {
        Canonicalizer canon = Canonicalizer.getInstance(Canonicalizer.ALGO_ID_C14N_OMIT_COMMENTS);
        byte canonXmlBytes[] = canon.canonicalize(xml.getBytes());
        return new String(canonXmlBytes);
    }

    public static String prettyFormat(String input) throws TransformerException, ParserConfigurationException, IOException, SAXException, InstantiationException, IllegalAccessException, ClassNotFoundException {
        InputSource src = new InputSource(new StringReader(input));
        Element document = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(src).getDocumentElement();
        Boolean keepDeclaration = input.startsWith("<?xml");
        DOMImplementationRegistry registry = DOMImplementationRegistry.newInstance();
        DOMImplementationLS impl = (DOMImplementationLS) registry.getDOMImplementation("LS");
        LSSerializer writer = impl.createLSSerializer();
        writer.getDomConfig().setParameter("format-pretty-print", Boolean.TRUE);
        writer.getDomConfig().setParameter("xml-declaration", keepDeclaration);
        return writer.writeToString(document);
    }
}

它是在单元测试中用于全字符串 xml 比较的好工具。

private void assertXMLEqual(String expected, String actual) throws ParserConfigurationException, IOException, SAXException, CanonicalizationException, InvalidCanonicalizerException, TransformerException, IllegalAccessException, ClassNotFoundException, InstantiationException {
    String canonicalExpected = prettyFormat(toCanonicalXml(expected));
    String canonicalActual = prettyFormat(toCanonicalXml(actual));
    assertEquals(canonicalExpected, canonicalActual);
}
于 2014-10-14T12:47:25.197 回答
1

我看到一个答案Scala是 ,所以这里是另一个答案,Groovy以防万一有人觉得它有趣。默认缩进为 2 步,XmlNodePrinter构造函数也可以传递另一个值。

def xml = "<tag><nested>hello</nested></tag>"
def stringWriter = new StringWriter()
def node = new XmlParser().parseText(xml);
new XmlNodePrinter(new PrintWriter(stringWriter)).print(node)
println stringWriter.toString()

如果 groovy jar 在类路径中,则使用 Java

  String xml = "<tag><nested>hello</nested></tag>";
  StringWriter stringWriter = new StringWriter();
  Node node = new XmlParser().parseText(xml);
  new XmlNodePrinter(new PrintWriter(stringWriter)).print(node);
  System.out.println(stringWriter.toString());
于 2015-05-01T20:42:24.943 回答
1

如果您不需要缩进那么多,但需要几个换行符,那么简单的正则表达式就足够了......

String leastPrettifiedXml = uglyXml.replaceAll("><", ">\n<");

代码很好,不是因为缺少缩进而导致的结果。


(有关缩进的解决方案,请参阅其他答案。)

于 2015-08-20T13:20:46.197 回答
1

Underscore-java有静态方法U.formatXml(string)活生生的例子

import com.github.underscore.U;

public class MyClass {
    public static void main(String args[]) {
        String xml = "<tag><nested>hello</nested></tag>";

        System.out.println(U.formatXml("<?xml version=\"1.0\" encoding=\"UTF-8\"?><root>" + xml + "</root>"));
    }
}

输出:

<?xml version="1.0" encoding="UTF-8"?>
<root>
   <tag>
      <nested>hello</nested>
   </tag>
</root>
于 2019-02-14T04:15:00.643 回答
0

试试这个:

 try
                    {
                        TransformerFactory transFactory = TransformerFactory.newInstance();
                        Transformer transformer = null;
                        transformer = transFactory.newTransformer();
                        StringWriter buffer = new StringWriter();
                        transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
                        transformer.transform(new DOMSource(element),
                                  new StreamResult(buffer)); 
                        String str = buffer.toString();
                        System.out.println("XML INSIDE IS #########################################"+str);
                        return element;
                    }
                    catch (TransformerConfigurationException e)
                    {
                        e.printStackTrace();
                    }
                    catch (TransformerException e)
                    {
                        e.printStackTrace();
                    }
于 2016-05-14T00:16:38.127 回答
0

在提出自己的解决方案之前,我应该先查找此页面!无论如何,我的使用 Java 递归来解析 xml 页面。此代码完全独立,不依赖第三方库。另外..它使用递归!

// you call this method passing in the xml text
public static void prettyPrint(String text){
    prettyPrint(text, 0);
}

// "index" corresponds to the number of levels of nesting and/or the number of tabs to print before printing the tag
public static void prettyPrint(String xmlText, int index){
    boolean foundTagStart = false;
    StringBuilder tagChars = new StringBuilder();
    String startTag = "";
    String endTag = "";
    String[] chars = xmlText.split("");
    // find the next start tag
    for(String ch : chars){
        if(ch.equalsIgnoreCase("<")){
            tagChars.append(ch);
            foundTagStart = true;
        } else if(ch.equalsIgnoreCase(">") && foundTagStart){
            startTag = tagChars.append(ch).toString();
            String tempTag = startTag;
            endTag = (tempTag.contains("\"") ? (tempTag.split(" ")[0] + ">") : tempTag).replace("<", "</"); // <startTag attr1=1 attr2=2> => </startTag>
            break;
        } else if(foundTagStart){
            tagChars.append(ch);
        }
    }
    // once start and end tag are calculated, print start tag, then content, then end tag
    if(foundTagStart){
        int startIndex = xmlText.indexOf(startTag);
        int endIndex = xmlText.indexOf(endTag);
        // handle if matching tags NOT found
        if((startIndex < 0) || (endIndex < 0)){
            if(startIndex < 0) {
                // no start tag found
                return;
            } else {
                // start tag found, no end tag found (handles single tags aka "<mytag/>" or "<?xml ...>")
                printTabs(index);
                System.out.println(startTag);
                // move on to the next tag
                // NOTE: "index" (not index+1) because next tag is on same level as this one
                prettyPrint(xmlText.substring(startIndex+startTag.length(), xmlText.length()), index);
                return;
            }
        // handle when matching tags found
        } else {
            String content = xmlText.substring(startIndex+startTag.length(), endIndex);
            boolean isTagContainsTags = content.contains("<"); // content contains tags
            printTabs(index);
            if(isTagContainsTags){ // ie: <tag1><tag2>stuff</tag2></tag1>
                System.out.println(startTag);
                prettyPrint(content, index+1); // "index+1" because "content" is nested
                printTabs(index);
            } else {
                System.out.print(startTag); // ie: <tag1>stuff</tag1> or <tag1></tag1>
                System.out.print(content);
            }
            System.out.println(endTag);
            int nextIndex = endIndex + endTag.length();
            if(xmlText.length() > nextIndex){ // if there are more tags on this level, continue
                prettyPrint(xmlText.substring(nextIndex, xmlText.length()), index);
            }
        }
    } else {
        System.out.print(xmlText);
    }
}

private static void printTabs(int counter){
    while(counter-- > 0){ 
        System.out.print("\t");
    }
}
于 2017-11-04T04:18:40.080 回答
-1

我试图实现类似的东西,但没有任何外部依赖。该应用程序已经在使用 DOM 来格式化只是为了记录 XML!

这是我的示例片段

public void formatXML(final String unformattedXML) {
    final int length = unformattedXML.length();
    final int indentSpace = 3;
    final StringBuilder newString = new StringBuilder(length + length / 10);
    final char space = ' ';
    int i = 0;
    int indentCount = 0;
    char currentChar = unformattedXML.charAt(i++);
    char previousChar = currentChar;
    boolean nodeStarted = true;
    newString.append(currentChar);
    for (; i < length - 1;) {
        currentChar = unformattedXML.charAt(i++);
        if(((int) currentChar < 33) && !nodeStarted) {
            continue;
        }
        switch (currentChar) {
        case '<':
            if ('>' == previousChar && '/' != unformattedXML.charAt(i - 1) && '/' != unformattedXML.charAt(i) && '!' != unformattedXML.charAt(i)) {
                indentCount++;
            }
            newString.append(System.lineSeparator());
            for (int j = indentCount * indentSpace; j > 0; j--) {
                newString.append(space);
            }
            newString.append(currentChar);
            nodeStarted = true;
            break;
        case '>':
            newString.append(currentChar);
            nodeStarted = false;
            break;
        case '/':
            if ('<' == previousChar || '>' == unformattedXML.charAt(i)) {
                indentCount--;
            }
            newString.append(currentChar);
            break;
        default:
            newString.append(currentChar);
        }
        previousChar = currentChar;
    }
    newString.append(unformattedXML.charAt(length - 1));
    System.out.println(newString.toString());
}
于 2019-06-10T18:16:13.187 回答