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如何在 mysql.for 中用 5 行相同的数据替换一行。例如我有这个表

 id   |   companyId   |      name       |  open  |  close
 1    |    1          |    mon-fri      |  10:00 |  19:00  
 2    |    1          |      sat        |  10:00 |  12:00 
 3    |    1          |      sun        |  10:00 |  12:00 
 4    |    2          |    mon-fri      |  10:00 |  16:00  
 5    |    2          |      sat        |  10:00 |  13:00 
 6    |    2          |      sun        |  10:00 |  13:00

我想将其 mon-fri 的名称字段转换为 mon 、 tues 、 wed 、 thur 、 fri 。

 id   |   companyId   |      name       |  open  |  close
 1    |    1          |    mon     |  10:00 |  19:00  
 2    |    1          |    tues    |  10:00 |  19:00 
 3    |    1          |    wed     |  10:00 |  19:00 
 4    |    1          |    thur    |  10:00 |  19:00   
 5    |    1          |    fri     |  10:00 |  19:00  
 6    |    1          |    sat     |  10:00 |  12:00 
 7    |    1          |    sun     |  10:00 |  12:00 
.
.
.
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1 回答 1

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你不能通过 a 来做到这一点UPDATE，但你可以做的是一系列INSERT INTO ... SELECT使用一些字符串文字，然后是 aDELETE来删除你展开的行。

/* First insert a row for each mon,tue,wed,thur,fri */
/* Column values are copied from the existing mon-fri row, and use the literal strings 'mon', 'tue', etc as the new `name` */
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
  SELECT `companyId`, 'mon', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
  SELECT `companyId`, 'tue', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
  SELECT `companyId`, 'wed', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
  SELECT `companyId`, 'thur', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
  SELECT `companyId`, 'fri', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'

/* Then delete the original mon-fri rows which you just expanded out */
DELETE FROM yourtable WHERE `name` = 'mon-fri'

http://sqlfiddle.com/#!2/cae33/1

（归功于：这个出色的建议是Andriy M在未经请求的编辑中的作品）

您还可以通过使用虚拟表来减少语句的数量以及表扫描的数量，如下所示：

/* Cross-join the existing 'mon-fri' rows with a virtual table of day names
   of 'mon' through 'fri' and insert the resulting set back into your table */
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
  SELECT t.`companyId`, v.`name`, t.`open`, t.`close`
  FROM yourtable t
  CROSS JOIN (
    SELECT 'mon' AS `name` UNION ALL
    SELECT 'tue' UNION ALL
    SELECT 'wed' UNION ALL
    SELECT 'thur' UNION ALL
    SELECT 'fri'
  ) v
  WHERE t.`name` = 'mon-fri';

/* Then delete the original mon-fri rows which you just expanded out */
DELETE FROM yourtable WHERE `name` = 'mon-fri';

http://sqlfiddle.com/#!2/98e35/1

评论后更新：

插入行时强制它们的顺序没有真正的价值，最好在SELECT.

要按天订购，companyId无论采用哪种方式，都需要做一些工作。您可以调用LOWER(STR_TO_DATE())并%a比较工作日值，但是您还需要更改您的thurto，thu因为这是 MySQL 的缩写方式。这会导致一堆函数调用。

相反，您可以使用 aCASE....来ORDER BY为每一天分配序数值，例如：

ORDER BY
 companyId,
 CASE `name`
   WHEN 'sun' THEN 1 
   WHEN 'mon' THEN 2
   WHEN 'tue' THEN 3
   WHEN 'wed' THEN 4
   WHEN 'thur' THEN 5
   WHEN 'fri' THEN 6
   WHEN 'sat' THEN 7
 ELSE 8 END

不过，上述两种方法都不会对索引友好。

如果您需要提高性能，我建议您'mon','tue','wed'首先不要存储字符串等，而是存储它们关联的工作日值。详情请参阅DAYOFWEEK()。

于 2012-12-15T20:14:17.997 回答