休眠 V.4.1.8 最终版
春季：3.1.3 发布
场景：在客户注册过程中，用户将填写完整的来自。他可以在完成表单之前多次保存表单，然后单击提交以完成内容。只有在最终提交后，应用程序才会创建客户 ID。为了实现这个功能，我创建了 2 个基于相同 POJO 的表。参考： 将同一个 POJO 映射到多个表
问题： 将数据保存到客户表中时。hibernate 将记录插入地址表并直接插入家庭表，但忽略客户表。因此抛出异常：无法添加或更新子行：外键约束失败
请在 custDetail 对象进入备份表和客户表时查看 sql 序列。
插入备份表
Hibernate: insert into mypack.address_bk (address1, address2, city, emailAddress, faxNo, landLineNo, mobileNo, pincode, state, verified) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into mypack.address_bk (address1, address2, city, emailAddress, faxNo, landLineNo, mobileNo, pincode, state, verified) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into mypack.address_bk (address1, address2, city, emailAddress, faxNo, landLineNo, mobileNo, pincode, state, verified) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into mypack.customer_bk (version, custId, custBirthDate, custEducation, custFirstName, custGender, custLastName, custMiddleName, custTitle, exServiceManFlag, fatherFullName, handicappedFlag, motherFullName, staffFlag, status, userId, bankCode, branchCode, customerPhoto, currentAddress, permanentAddress, officeAddress) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into mypack.family_bk (custId, memberName, relation, birthDate, gender, occupation) values (?, ?, ?, ?, ?, ?)
插入客户表
Hibernate: insert into mypack.address (address1, address2, city, emailAddress, faxNo, landLineNo, mobileNo, pincode, state, verified) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into mypack.address (address1, address2, city, emailAddress, faxNo, landLineNo, mobileNo, pincode, state, verified) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into mypack.address (address1, address2, city, emailAddress, faxNo, landLineNo, mobileNo, pincode, state, verified) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
Hibernate: insert into mypack.family (custId, memberName, relation, birthDate, gender, occupation) values (?, ?, ?, ?, ?, ?)
SQL Error: 1452, SQLState: 23000 Cannot add or update a child row: a foreign key constraint fails
表定义：
<class entity-name="com.boss.mypack.model.Customer" lazy="true"
name="com.boss.mypack.model.Customer" polymorphism="explicit"
schema="mypack" table="customer">
<id length="15" name="custId" type="string">
<column length="20" name="custId" />
<generator class="assigned" />
</id>
<version column="version" generated="never" name="version"
type="integer" unsaved-value="null" />
<property generated="never" lazy="false" name="tempId" type="java.lang.Integer">
<column name="tempId" not-null="false" />
</property>
<many-to-one cascade="all" class="com.boss.mypack.model.Address"
entity-name="com.boss.mypack.model.Address" fetch="select" lazy="false"
name="OfficeAddress">
<column name="officeAddress" />
</many-to-one>
<set cascade="all" fetch="select" inverse="true" lazy="true" name="family"
sort="unsorted" table="family">
<key>
<column length="20" name="custId" />
</key>
<one-to-many class="com.boss.mypack.model.Family"
entity-name="com.boss.mypack.model.Family" />
</set>
</class>
后桌：
<class entity-name="bkCustomer" lazy="true"
name="com.boss.mypack.model.Customer" polymorphism="explicit"
schema="mypack" table="customer_bk">
<id length="4" name="tempId" type="java.lang.Integer">
<column length="20" name="tempId" />
<generator class="identity" />
</id>
<version column="version" generated="never" name="version"
type="integer" unsaved-value="null" />
<property generated="never" lazy="false" name="custId" type="string">
<column length="20" name="custId" />
</property>
<many-to-one cascade="all" class="com.boss.mypack.model.Address"
entity-name="bkAddress" fetch="select" lazy="false" name="OfficeAddress">
<column name="officeAddress" />
</many-to-one>
<set cascade="all" fetch="select" inverse="true" lazy="true" name="family"
sort="unsorted" table="bkfamily">
<key>
<column length="20" name="custId" />
</key>
<one-to-many class="com.boss.mypack.model.Family"
entity-name="bkFamily" />
</set>
</class>
保存方法：
public void saveCustomer(Customer custDetails) {
Session session;
session = getSessionFactory().getCurrentSession();
session.beginTransaction();
try {
session.saveOrUpdate("bkCustomer", custDetails);
session.getTransaction().commit();
} catch (Exception e) {
session.getTransaction().rollback();
e.printStackTrace();
}
}
批准客户方法
@Override
public void approveCustomer(Customer custDetails) {
Session session = null;
// Saving Customer details to Database
try {
//TODO:Need to this in single session, In failure, every changes should get rolled back.
//Removing from backup Table
session = getSessionFactory().getCurrentSession();
session.beginTransaction();
session.delete("bkCustomer", custDetails);
session.getTransaction().commit();
System.out.println("**** Record Deleted ****");
session = getSessionFactory().getCurrentSession();
session.beginTransaction();
// check to see whether this is new customer.
if (custDetails.getCustId() == null) {
// New Customer - Generate Customer ID
custDetails.setTempId(null);
custDetails.setCustId(getNextCustomerCode(session));
// Clear all Auto Generated IDs
custDetails.getCurrentAddress().setAddressId(null);
custDetails.getOfficeAddress().setAddressId(null);
custDetails.getPermanentAddress().setAddressId(null);
// custDetails.getPhotoMaster().setPhotoId(0);
Set<Family> familyMembers = custDetails.getFamily();
for (Family member : familyMembers) {
member.setMemberId(null);
}
} else {
System.out.println("**** This customer is already present in Database");
}
custDetails.setStatus("A");
session.saveOrUpdate("com.boss.mypack.model.Customer", custDetails);
//Following works properly, updates Backup tables
//session.saveOrUpdate("bkCustomer", custDetails);
session.getTransaction().commit();
// Saving Customer details to LDAP.
// ldapDAO.saveOrUpdate(custDetails);
// session.getTransaction().commit();
} catch (Exception e) {
session.getTransaction().rollback();
e.printStackTrace();
}
}
我在客户表上没有任何异常。我尝试使用 session.clear/flash/evict/merge/replicate 等分离对象，使用 DOZER 但没有进展。即使我试图删除级联选项。
我不确定哪里出了问题。请帮忙。
问候，
希里什语