c - 如何在文本文件中找到单词的中间字符？

Question

如何在文本文件中找到第一个单词的中间字符，然后用它来计算该字符的其他出现次数？我有计算文本文件中单词的函数和计算第一个单词长度的函数。

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <conio.h>
#define maxBuf 128

void howMany(FILE * file);
void words(FILE * file);

int main() {
FILE *temp, *file;
file = fopen("test.txt", "r");
temp = fopen("temp.txt","w");
char sd1[maxBuf];

howMany(file);
words(file);

fclose(file);
fclose(temp);

unlink("test.txt");
rename("temp.txt","test.txt");

return 0;  
}
void howMany(FILE * file){
char sd1[maxBuf];
file = fopen("test.txt", "r");
int i, z, c;
char word[1000];

while (!feof(file)) {
        if(fscanf(file,"%s",word)==1);
        printf("word read is: %s\n", word);
        printf("word read is: %i\n", strlen(word));                  
        break;
}
}
void words(FILE * file){
file = fopen("test.txt", "r");
char sd1[maxBuf];
int iwant; 
int nwords = 0; 

char word[1000];
int i, z;

while (fscanf(file, "%s", sd1) == 1) {

++nwords;
}
printf("There are %i words. \n", nwords);
}

Answer 1

缩进你的代码。

检查函数的结果，如fopen, fgets......

MAX_BUF是一个更好的名字maxBuf

size_t middle, n = strlen(sd1);
middle = (n / 2) + (n % 2 != 0);