1

我从 Google App Engine 获取数据作为字符串,所以我必须在一个线程中完成。接下来我想在 ListView 中显示它,我正在尝试执行类似以下代码的操作:

public void ShowContacts (){    
    new Thread(new Runnable() {         
        @Override
        public void run() {
            try
            {
                final RestClient client = new RestClient("http://xxx.appspot.com/client");
                client.AddParam("userName", "user");
                client.Execute(RequestMethod.GET);
                _listView.post(new Runnable() {                 
                    @Override
                    public void run() {
                        String s = client.getResponse();
                        String[] items = s.split(";");

                        //adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, android.R.id.text1, items);                         
                        //_listView.setAdapter(adapter);                            
                    }
                });                             
            }
            catch (Exception e)
            {

            }
        }
    }).start();
}     

这段代码对我不起作用。有没有办法从线程中获取一些值并将其设置为全局变量或直接在线程中构造一个 ArrayAdapter 或其他东西?

4

1 回答 1

1

使用AsyncTask从服务器获取数据并添加到 ListView 为:

public class getDatafromserver extends AsyncTask<String, Void, String> {

          @Override

      protected void onPreExecute() {
      }

      @Override
      protected String doInBackground(String... params) {

         final RestClient client = new 
                             RestClient("http://xxx.appspot.com/client");
            client.AddParam("userName", "user");
            client.Execute(RequestMethod.GET);
          String s = client.getResponse();
          return s  ;
      }      

      @Override
      protected void onPostExecute(String result) {                           
                    String[] items = result.split(";");

                    adapter = new ArrayAdapter<String>(this, 
                android.R.layout.simple_list_item_1, android.R.id.text1, items);                         
                    _listView.setAdapter(adapter);  
      }
}

从您的 Ui 线程启动此 AsyncTask:

new getDatafromserver().execute("");
于 2012-12-14T21:19:36.703 回答