3

我想在基于 AJAX 响应的框中即时构建 s;即如果 responseText 为 3,我想构建 3 个选项:

<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>

以下代码正在工作:

$("#PAG_PLACEMENT").change(function(){
            $.ajax({
            type: "post",
            url: "untitled.asp",
            data: "iLanguage=1&iPlacement="+$("#PAG_PLACEMENT").val(),
            success: function(responseText){
                    //alert(parseInt(responseText));
                    opts = parseInt(responseText);
                            var routeSelect = $("#PAG_POSITION").get(0);
                            routeSelect.options.length = 0; //reset to zero length
                            for(var i = 0; i < opts; ++i) {
                            routeSelect.options[i] = new Option(i+1,i+1);
                            }
                    }
            });
    });

但我想“jQueryfy”这部分:

var routeSelect = $("#PAG_POSITION").get(0);
    routeSelect.options.length = 0; //reset to zero length
    for(var i = 0; i < opts; ++i) {
    routeSelect.options[i] = new Option(i+1,i+1);
}

更多,有时 responseText 为空(页面为空白),解析它当然会给出“NaN”:好吧,在这种情况下,我想用一个简单的填充:

<option value="0">0<value>

我是一个 JS 新手,不知道该怎么做...拜托,你能帮忙吗?

4

1 回答 1

4

你可以做:

var routeSelect = $("#PAG_POSITION").get(0);

routeSelect.html(''); //clear-out options

if (isNaN(opts) || opts == 0) {
    //Handles case where your response is invalid or zero
    routeSelect.append($('<option/>').val(0).html(0));
} else {
    //Add n items to the dropdown
    for(var i = 0; i < opts; ++i) {
        routeSelect.append($('<option/>').val(i).html(i));
    }
}

希望这可以帮助。

于 2009-09-07T08:55:51.790 回答