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我有以下查询：

SELECT 
(substr(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,'), 2, length(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,')) - 2)) ,
xex.xex_xexc_k,
  FROM qot, sec, exc, ctr, xcx, xex, xexc, xcrr, crr
 WHERE qot_source = 'X'
       AND qot_id = 2029557521
       AND nvl(qot_real_exc_id, qot_exc_id) = exc_id
       AND exc_ctr_id = ctr_id
       AND qot_sec_id = sec_id
       AND nvl(qot_real_exc_id, qot_exc_id) = xex_exc_id(+)
       AND qot_crr_id = xcx_crr_id(+)
       AND xex_xexc_k = xexc_k(+)
       AND xcx_xcrr_k = xcrr_k(+)
       AND qot_crr_id = crr_id(+)
       AND qot_status IN (1, 2)
      AND (qot_sup_xpressfeed IS NULL OR to_number(substr(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,'), 2, length(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,')) - 2)) = xexc_k);

当我注释掉最后一个限制时AND (qot_sup_xpressfeed IS NULL OR to_number(substr(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,'), 2, length(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,')) - 2)) = xexc_k);，我得到了结果：

1135    67
1135    111
1135    549
1135    246
1135    103
1135    564
1135    1135
1135    21

如您所见，我有一排：

1135 1135

但是当我添加最后一个限制时，我没有得到任何结果：

 AND (qot_sup_xpressfeed IS NULL OR to_number(substr(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,'), 2, length(REGEXP_SUBSTR(qot_sup_xpressfeed, ',[^,]+,')) - 2)) = xexc_k);

我希望我会得到 1 个结果（提到的1135 1135）。我究竟做错了什么？

4

1 回答 1

1

您正在选择xex.xex_xexc_k，而您的测试正在进行xexc_k。由于这是一个 OUTER JOIN，它们可能会有所不同。当你与xex.xex_xexc_k而不是比较时会发生什么？

于 2012-12-14T11:41:40.123 回答