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121214 11:54:30 [Warning] Unsafe statement written to the binary log using statement format since BINLOG_FORMAT = STATEMENT. Statements writing to a table with an auto-increment column after selecting from another table are unsafe because the order in which rows are retrieved determines what (if any) rows will be written. This order cannot be predicted and may differ on master and the slave. Statement: update db_ds_pax p
        set p.mbp_id = 8861912, updated_ts = now()
        where p.flight_id = 2506912 
        and p.logically_deleted = 0
        and (
            exists (
                    select * from db_bkg_passenger bkgp 
                    where bkgp.bkg_pax_id = p.bkg_pax_id
                    and bkgp.ticket_num = '2202326623256'
                    and bkgp.logically_deleted = 0 )
            or exists (
                    select * from db_dcs_pax dcsp 
                    where dcsp.dcs_pax_id = p.dcs_pax_id
                    and dcsp.ticket_num = '2202326623256'
                    and dcsp.logically_deleted = 0 ))

这个声明中有什么不安全的？我没有插入任何东西，只是在更新。实际上，我什至没有选择任何将用于更新的东西。

我曾尝试使用左连接重写，但它仍然抱怨。我还认为可能updated_ts = now()是罪魁祸首并将其设置为固定时间，但仍然是相同的警告。

服务器是Oracle的5.5.27

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1 回答 1

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从另一个表中选择后写入具有自动增量列的表的语句是不安全的，因为检索行的顺序决定了将写入哪些（如果有）行。此顺序无法预测，并且可能在主服务器和从服务器上有所不同

我什么也没做，只是从警告消息中复制粘贴了解释。

所以似乎UPDATE被视为“写入表格”

于 2012-12-14T11:28:37.653 回答