我正在尝试制作一个复制目录子项的程序,但我无法标记所有特定名称,因为它们在每个文件夹中都不同。这是我的代码,但如果源是“C:\src”并且输出是“C:\dst”,它将创建文件夹“C:\dst\src(children files)”,但我想制作“C:\dst(子文件)”。任何人都可以帮忙吗?
public static void copy(File source, File destination) throws IOException {
if (source == null) {
throw new NullPointerException("Null Source");
}
if (destination == null) {
throw new NullPointerException("Null Destination");
}
if (source.isDirectory()) {
copyDirectory(source, destination);
} else {
copyFile(source, destination);
}
}
//converts to location
public static void copyDirectory(File source, File destination) throws IOException {
copyDirectory(source, destination, null);
}
public static void copyDirectory(File source, File destination, FileFilter filter) throws IOException {
File nextDirectory = new File(destination, source.getName());
if (!nextDirectory.exists() && !nextDirectory.mkdirs()) {// create the directory if necessary...
Object[] filler = {nextDirectory.getAbsolutePath()};
String message = "Dir Copy Failed";
throw new IOException(message);
}
File[] files = source.listFiles();
for (int n = 0; n < files.length; ++n) {// and then all the items below the directory...
if (filter == null || filter.accept(files[n])) {
if (files[n].isDirectory()) {
copyDirectory(files[n], nextDirectory, filter);
} else {
copyFile(files[n], nextDirectory);
}
}
}
}
public static void copyFile(File source, File destination) throws IOException {
// what we really want to do is create a file with the same name in that dir
if (destination.isDirectory()) {
destination = new File(destination, source.getName());
}
FileInputStream input = new FileInputStream(source);
copyFile(input, destination);
}
public static void copyFile(InputStream input, File destination) throws IOException {
OutputStream output = null;
try {
output = new FileOutputStream(destination);
byte[] buffer = new byte[1024];
int bytesRead = input.read(buffer);
while (bytesRead >= 0) {
output.write(buffer, 0, bytesRead);
bytesRead = input.read(buffer);
}
} catch (Exception e) {
//
} finally {
input.close();
output.close();
}
input = null;
output = null;
}