我建议使用正则表达式:
import re
ss = '''Country Count Sales
USA , 3 , 65000
UK , 3 , 4000
IND , 8 , g
SPA , ju , 9000
NTH , 5 , 80000
XSZ , rob , k3'''
with open('fofo.txt','w') as f:
f.write(ss)
print ss
print
delimiter = ','
regx = re.compile('(.+?(?:{0}))'
'(( *\d+?)| *.+?)'
'( *(?:{0}))'
'(( *\d+?)| *.+?)'
'( *\r?\n?)$'.format(delimiter))
def READ(filepath, regx = regx):
with open(filepath,'rb+') as f:
yield f.readline()
for line in f:
if None in regx.match(line).group(3,6):
g2,g3,g5,g6 = regx.match(line).group(2,3,5,6)
tr = ('%%%ds' % len(g2) % 'NaN' if g3 is None else g3,
'%%%ds' % len(g5) % 'NaN' if g6 is None else g6)
modified_line = regx.sub(('\g<1>%s\g<4>%s\g<7>' % tr),line)
print ('------------------------------------------------\n'
'%r with aberration\n'
'%r modified line'
% (line,modified_line))
yield modified_line
else:
yield line
with open('modified.txt','wb') as g:
g.writelines(x for x in READ('fofo.txt'))
结果
Country Count Sales
USA , 3 , 65000
UK , 3 , 4000
IND , 8 , g
SPA , ju , 9000
NTH , 5 , 80000
XSZ , rob , k3
------------------------------------------------
'IND , 8 , g\r\n' with aberration
'IND , 8 , NaN\r\n' modified line
------------------------------------------------
'SPA , ju , 9000\r\n' with aberration
'SPA , NaN , 9000\r\n' modified line
------------------------------------------------
'XSZ , rob , k3' with aberration
'XSZ , NaN , NaN' modified line