我正在使用 AJAX 功能。我使用 AJAX 将 3 个变量传递到下一页。当我添加第 4 个变量时,不会调用该函数。
Code:
     <script language="javascript" type="text/javascript">
            //Browser Support Code
            function ajaxFunction(){
                var ajaxRequest;  // The variable that makes Ajax possible!
                try{
                    // Opera 8.0+, Firefox, Safari
                    ajaxRequest = new XMLHttpRequest();
                } catch (e){
                    // Internet Explorer Browsers
                    try{
                        ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
                    } catch (e) {
                        try{
                            ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
                        } catch (e){
                            // Something went wrong
                            alert("Your browser broke!");
                            return false;
                        }
                    }
                }
                // Create a function that will receive data sent from the server
                ajaxRequest.onreadystatechange = function(){
                    if(ajaxRequest.readyState == 4){
                        var ajaxDisplay = document.getElementById('ajaxDiv');
                        ajaxDisplay.innerHTML = ajaxRequest.responseText;
                    }
                }
             var count = document.getElementById('count').value;
             var type = document.getElementById('type').value;
             var sem = document.getElementById('sem').value;
              var rid = document.getElementById('room').value;
          ajaxRequest.open("GET", "add_requi_ajax.php?count=" + count+"&type="+ type+"&sem="+sem+"&rid="+rid, true);
        ajaxRequest.send(null);
    };
</script>