select out.a,out.b from out
pivot (count([event]) for [date] in ([Mon],[Tues])) as event_count
group by out.a,out.b
在执行此查询时,我收到以下错误:
多部分标识符 out.a,out.b 无法绑定
select out.a,out.b from out
pivot (count([event]) for [date] in ([Mon],[Tues])) as event_count
group by out.a,out.b
在执行此查询时,我收到以下错误:
多部分标识符 out.a,out.b 无法绑定
删除GROUP BY
子句和out
列的别名,a
如下b
所示:
select a, b, [Mon], [Tues]
from out
pivot
(
count([event])
for [date] in ([Mon],[Tues])
) as event_count;
请注意:使用PIVOT
表运算符时,您不需要显式指定分组元素,在您的情况a, b
或源表中,您需要将其从查询和源表中删除。运算符将PIVOT
自动计算出您想要的列GROUP BY
,这些列是在您的情况下未在 thedate
或聚合元素中指定event
的列,其余列将是分组列。
这就是为什么您必须明确列出列名而不是 的原因FROM out
,以防表out
包含除 之外的列a, b, date, event
。在这种情况下,您必须这样做:
select a, b, [Mon], [Tues]
from
(
SELECT a, b, "date", "event"
FROM out
) t
pivot
(
count([event])
for [date] in ([Mon],[Tues])
) as event_count;
听起来您需要在 [Mon] 上替换 out.a 并在 [Tues] 上替换 out.b
SELECT [Mon], [Tues]
FROM out
PIVOT (
COUNT([event]) FOR [date] in ([Mon],[Tues])
) AS event_count
SQLFiddle上的演示
我不确定您的查询,但可能这就是您要查找的内容
Select a,b, [Mon],[Tues] from
(
Select a,b,date,event from out
group by a,b,date,event
)L
PIVOT
(
count(event) for [date] in ([Mon],[Tues])
) event_count