jsfiddle：http: //jsfiddle.net/X4uvD/
我试图让这个 jquery 代码只重写父 ul li 而不是 ul li 里面。
任何想法如何实现这一目标？
//This is for footer slider, it rewrites 1 ul into several uls that contain 4 li max.
// get the container, useful for later too...
var container = $(".fproductslides");
// get all available UL and LI elements...
// this doesn't order featured listings at the top of the list
// var li_elements = container.find("LI").clone();
// this does order featured listings at the top of the list
var li_elements = container.find("LI.slidefeatured").clone();
li_elements = li_elements.add(container.find('LI:not(.slidefeatured)').clone());
// remove the current content so that we can rebuild it for the slider...
container.find("UL").remove();
// build the slider container...
var slide_container = $("<div />");
slide_container.addClass("slides_container");
// tricky part: looping through the LI's and building each of the slides...
// first create some helpful variables...
var li_elements_per_slide = 3;
var li_counter = 0;
// create the first slide, with a UL to hold the LI's...
var current_li_div = $("<div />");
current_li_div.append($("<ul />"));
// loop through the LI's...
li_elements.each(function(index, element){
li_counter++;
var current_li = $(element).clone();
current_li_div.find("UL").append(current_li);
if (li_counter % li_elements_per_slide == 0)
{
// we've hit 4 in this list, so add the slide and make
// a new one, using same code as before...
container.append(current_li_div);
current_li_div = $("<div />");
current_li_div.append($("<ul />"));
}
});
// we might have an uneven number of LI's, so we need to check for this...
if (li_counter % li_elements_per_slide != 0)
container.append(current_li_div);