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基本上我已经让我的代码工作了，当页面加载时，图像开始在画布上一个接一个地显示，但是我希望图像在鼠标单击时开始显示，你能告诉我怎么做这个？

<script>

window.onload = function() {



var canvas=document.getElementById("myCanvas").addEventListener("mousedown",    function() // Selects the canvas element
var context=canvas.getContext("2d"); 

var img1 =new Image() //creates a variable for a new image
var img2 =new Image() //creates a variable for a new image
var img3 =new Image() //creates a variable for a new image
var img4 =new Image() //creates a variable for a new image

img1.src = "canvasimg1.png" // Gets image
img2.src = "canvasimg2.png" // Gets image
img3.src = "canvasimg3.png" // Gets image
img4.src = "canvasimg4.png" // Gets image

setTimeout(                                             // Settimeout - execute the passed function after the amount of milliseconds
    function() { context.drawImage(img1,23,20); }       // Function to be executed
, 1000);                                                // Amount of milliseconds to delay for

setTimeout(                                             // Settimeout - execute the passed function after the amount of milliseconds
    function() { context.drawImage(img2, 23, 60); }     // Function to be executed
, 6000);                                                // Amount of milliseconds to delay for

setTimeout(                                             // Settimeout - execute the passed function after the amount of milliseconds
    function() { context.drawImage(img3, 25, 120); }    // Function to be executed
, 11000);                                               // Amount of milliseconds to delay for

setTimeout(                                             // Settimeout - execute the passed function after the amount of milliseconds
    function() { context.drawImage(img4, 150, 180); }   // Function to be executed
, 16000);                                               // Amount of milliseconds to delay for
}

</script>
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1 回答 1

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如果您需要在单击画布时开始显示图像，则将四个 setTimeout 函数放在另一个函数中，并且仅在单击画布时才调用此函数！

 <canvas id="exemple" width="200" height="200" onclick="showImage()">


function showImage(){
    setTimout.....
     ....
   }
于 2012-12-12T22:36:37.527 回答