objective-c - 如何以数字格式获取月份中的日期？

Question

我要查找的是月份中的哪一天，例如 2、5、30 或 31。以整数形式，而不是字符串。我不是在寻找预定的日期，而是在他们所在的任何地方寻找今天的日期。

Answer 1

以上所有答案都是实现此目的的不好方法。这是正确的方法：

NSDate *date = [NSDate date];
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [calendar components:NSDayCalendarUnit fromDate:date];
NSInteger day = components.day;

Answer 2

NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"d"];
NSInteger day = [[dateFormat stringFromDate:[NSDate date]] intValue];

Answer 3

从 an 开始，NSDate然后通过NSDateFormatter.

https://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSDate_Class/Reference/Reference.html

https://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSDateFormatter_Class/Reference/Reference.html

Answer 4

这是可能有用的东西：

NSDate *theDate;

// Set theDate to the date you want
// For example, theDate = [NSDate date]; to get today's date

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
formatter.dateFormat = @"d";
NSString *theDayString = [formatter stringFromDate:theDate];
int theDay = theDayString.intValue;

NSLog (@"%d", theDay);

theDay包含您要查找的值！