1

我正在尝试为我的视图模型创建一个通用容器，以便可以在没有特定视图模型知识的情况下将常用方法应用于各种对象。容器和包含的对象如下所示：

var containedViewModel = function() {
  var self = this;
  self.id = ko.observable();
    ...
  self.doSomething = function() {
  alert('here');
  };

}

var ContainerModel = function(cRoot, cModel, cName) {
  var self = this;

  self.rootModel  = cRoot;                       // Root view model
  self.viewName   = cName;                       // viewModel container name
  self.refModel   = cModel;                      // viewModel reference
  self.viewModel  = ko.observable();             // Single view model
  self.viewModels = ko.observableArray();        // Array of view models

  self.init = function(rootModel) {
    self.viewModel = new self.refModel();
  } 
  self.doSomething = function() {
    self.rootModel.doSomeThing();    // This works
    self.refModel.doSomeThing();     // This does not work
    self.viewModel.doSomeThing();    // This does not work as well
  }

}

容器将通过如下调用创建：

var ParnentModel = function() {
  var self = this;
  self.id = ko.observable();
    ...
  self.container = new ContainerModel(self, containedViewModel, 'modelName');
    ...
  self.doSomething = function() {
  alert('here');
  };
};

在此示例中，rootModel 函数访问工作正常，因为实际的视图模型已创建并传递给容器。使用 'new self.refModel()' 和 'self.rootModel.doSomeThing()' 似乎可以按预期工作。当我尝试使用'self.viewModel.doSomeThing();' 淘汰赛抱怨它不是一个功能。

是否可以通过引用 viewModel 来访问 viewModels 函数。

任何帮助，将不胜感激。

4

2 回答 2

1

您快到了。请参阅我在代码中的评论。

var containedViewModel = function() {
  var self = this;
  self.id = ko.observable();
  self.doSomething = function() {
    alert('contained');
  };
  // I would prefer to have return self here
};

var ContainerModel = function(cRoot, cModel, cName) {
  var self = this;

  self.rootModel  = cRoot;                       // Root view model
  self.viewName   = cName;                       // viewModel container name
  self.refModel   = cModel;                      // viewModel reference
  self.viewModel  = ko.observable();             // Single view model
  self.viewModels = ko.observableArray();        // Array of view models

  self.init = function(rootModel) {
    // you meant this, right?
    self.viewModel(new self.refModel());
  }; 
  self.doSomething = function() {
    self.rootModel.doSomething();    // This works
    //self.refModel.doSomeThing();     // This does not work
    // need to unwrap the value, fixed typo
    self.viewModel().doSomething();    // This does not work as well
  };
};

var ParnentModel = function() {
  var self = this;
  self.id = ko.observable();
  self.container = new ContainerModel(self, containedViewModel, 'modelName');
  // missing call to init
  self.container.init();
  self.doSomething = function() {
      alert('parent');
  };
};

// execution
var p = new ParnentModel();
p.container.doSomething();

http://jsbin.com/arezew/1/edit

于 2012-12-12T07:53:20.393 回答
0

我认为您应该在像这样传递给 ContainerModel 时创建包含模型的实例：

self.container = new ContainerModel(self, new containedViewModel, 'modelName');
于 2012-12-12T07:41:10.367 回答