1

我正在尝试在 xml 文件中搜索这些事件：

<xml>  
<corpus>  
<body>  
<nonterminals>  
<graph>  
<s>  
<nt id="s9_509" cat="fcl"></nt>  

<nt id="s9_501" cat="pp">  
                <edge label="H" idref="s9_1"/>  
                <edge label="DP" idref="s9_502"/>  
                <edge label="STA" idref="s9_509"/>  
                <edge label="P" idref="s9_19"/>  
                <edge label="S" idref="s9_510"/>  
                <edge label="PU" idref="s9_25"/>  
            </nt>  
</nonterminals>  
</graph>  
</s>  
</body>  
</corpus>  
</xml>

我的代码是：

XPath xpath = XPathFactory.newInstance().newXPath();    
String path = "//xml//corpus//build//s//graph//nonterminals//nt";  
XPathExpression expr = xpath.compile(path);    
System.out.println("Query1: "+path);  
Object result = expr.evaluate(document, XPathConstants.NODESET);    
NodeList nodes = (NodeList) result;    
System.out.println("Number of nodes: "+nodes.getLength());  
for (int i = 0; i < nodes.getLength(); i++) {    
    System.out.println(nodes.item(i).getAttributes().getNamedItem("id").getNodeValue());

这个查询正确吗？是否存在另一种尝试方式？如何删除节点发现？

4

1 回答 1

0

如果这是您的 XML 的整个结构并且<xml>是您的根节点，我会说您的 XPath 应该是：

/xml/corpus/build/s/graph/非终端/nt

如果您想匹配每个 nt节点，无论它出现在文档中的哪个位置，您都可以使用：

//nt

有一些有用的免费工具可以查看 XPath 查询的结果，而无需预先编写 java：

http://xml-copy-editor.sourceforge.net/

http://www.xpathtester.com/

于 2012-12-11T17:33:25.887 回答