1

我正在使用 spring mvc 和 rest 开发客户端服务器应用程序。它的简单计算器服务，客户端调用服务器的方法来执行操作。

这是我的休息客户端代码restClient.java： 

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package com.blog.samples.client;

/**
 *
 * @author bhushan.baviskar
 */
import com.blog.samples.domain.Calculator;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.web.client.RestTemplate;

public class restClient {

  public static void main(String [] args)
  {
      restClient tmp = new restClient();
      tmp.calltoserver();
  }
  public void calltoserver() {
    ApplicationContext applicationContext = new ClassPathXmlApplicationContext("../../../../appContext.xml", restClient.class);
    RestTemplate restTemplate = applicationContext.getBean("restTemplate", RestTemplate.class);
    String url = "http://localhost:8080/rest/calc/4&3&+";
    Calculator calObj = (Calculator) restTemplate.getForObject(url, Calculator.class);
    System.out.println("details " + calObj.getDetails());
    System.out.println("done");
  }
}

这是我的 appContext.xml 文件： 

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
                           http://www.springframework.org/schema/beans/spring-beans.xsd">

  <bean id="restTemplate" class="org.springframework.web.client.RestTemplate">
        <property name="messageConverters">
      <bean id="messageConverter" class="org.springframework.http.converter.xml.MarshallingHttpMessageConverter">
        <property name="marshaller" ref="xstreamMarshaller" />
        <property name="unmarshaller" ref="xstreamMarshaller" />
      </bean>
    </property>
  </bean>

  <bean id="xstreamMarshaller" class="org.springframework.oxm.xstream.XStreamMarshaller">
    <property name="aliases">
    <props>
      <prop key="Calculator">com.blog.samples.webservices.rest.CalcController</prop>
    </props>
    </property>
  </bean>

</beans>

我收到 json 格式的响应，但是当我执行 restclient.java 文件时它说： 

DEBUG: [Dec-11 16:54:39,706] web.client.RestTemplate - GET request for "http://localhost:8080/rest/calc/4&3&+" resulted in 200 (OK)

Exception in thread "main" org.springframework.web.client.RestClientException: **Could not extract response: no suitable HttpMessageConverter found for response type** [com.blog.samples.domain.Calculator] and content type [text/plain;charset=UTF-8]
    at org.springframework.web.client.HttpMessageConverterExtractor.extractData(HttpMessageConverterExtractor.java:84)
    at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:446)
    at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:401)
    at org.springframework.web.client.RestTemplate.getForObject(RestTemplate.java:199)
    at com.blog.samples.client.restClient.calltoserver(restClient.java:27)
    at com.blog.samples.client.restClient.main(restClient.java:21)
------------------------------------------------------------------------

我是 Spring Rest 客户端开发的新手，因此将不胜感激。

如果有人知道请。告诉我如何处理响应？

4

1 回答 1

3

这是因为 MappingJacksonHttpMessageConverter 未注册到您的 restTemplate。默认情况下，类路径中存在的所有类型的 MessageConverters 都将被注册。

您应该在 xml 中删除 bean restTemplate 的属性 messageConverters 以获得默认的 messageconverters，或者您必须将 MappingJacksonHttpMessageConverter 添加到 xml 中的 messageConverters 列表中。

希望这可以帮助

于 2013-02-13T09:42:47.997 回答