我有一个表格,其中一列有逗号分隔值,我想要在行中..
喜欢
col1
3,4,5
5,6,6
返回结果应该是
col1
3
4
5
5
6
6
declare @tbl table(data nvarchar(100))
insert into @tbl values('1,2,3')
insert into @tbl values('4,5,6')
insert into @tbl values('7,8,9')
SELECT
Split.a.value('.', 'VARCHAR(100)') AS String
FROM (SELECT data,
CAST ('<M>' + REPLACE(data, ',', '</M><M>') + '</M>' AS XML) AS String
FROM @tbl) AS A CROSS APPLY String.nodes ('/M') AS Split(a);
You can use a recursive query to perform this split:
;with cte (item, list) as
(
select
cast(left(col1, charindex(',',col1+',')-1) as varchar(50)) item,
stuff(col1, 1, charindex(',',col1+','), '') list
from yourtable
union all
select
cast(left(list, charindex(',',list+',')-1) as varchar(50)) item,
stuff(list, 1, charindex(',',list+','), '') list
from cte
where list > ''
)
select item
from cte
我相信下面解释了如何遍历逗号分隔值。您可以将它们插入另一个变量以获得所需的输出。