<?php
$host = 'www.yourtargeturl.com';
$service_uri = '/detect_referal.php';
$vars ='additional_option1=yes&additional_option2=un';
$header = "Host: $host\r\n";
$header .= "User-Agent: PHP Script\r\n";
$header .= "Content-Type: application/x-www-form-urlencoded\r\n";
$header .= "Referer: http://www.google.com/search?hl=en&q=jigh&btnG=Google+Search \r\n";
$header .= "Content-Length: ".strlen($vars)."\r\n";
$header .= "Connection: close\r\n\r\n";
$fp = fsockopen("".$host,80, $errno, $errstr);
if (!$fp) {
echo "$errstr ($errno)<br/>\n";
echo $fp;
} else {
fputs($fp, "POST $service_uri HTTP/1.1\r\n");
fputs($fp, $header.$vars);
fwrite($fp, $out);
while (!feof($fp)) {
echo fgets($fp, 128);
}
fclose($fp);
}
?>
这正在改变$_SERVER['HTTP_REFERER']
. 我该如何改变$_SERVER['REMOTE_ADDR']
。我应该附加什么代码$header
?