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我有一个寻找两件事的搜索。项目和联系人。他们每个人都有自己的桌子，拥有自己独特的属性。我能够成功地相互独立地搜索每个并将结果返回到两个列表视图。但它是否丑陋并且分页已成为一个问题，所以我必须将这两个表转换为可以显示为搜索结果的类似结果。这些结果彼此之间没有直接关系。

正在让group t3 by new我失望。我是否必须将它们分组才能使其成为类似的结果？例如，结果当前显示在 ListView 中<%#Eval("ItemName") %>

ItemContext db = new ItemContext(); //DB connection (Item,Contact)
            var q = (from t1 in db.Item
                     join t2 in db.Categories on t1.CategoryID equals t2.CategoryID
                     join t7 in db.Divisions on t1.DivisionID equals t7.DivisionID
                     from t3 in db.Contacts
                     join t4 in db.Categories on t3.CategoryID equals t4.CategoryID
                     join t5 in db.Divisions on t3.DivisionID equals t5.DivisionID
                     join t6 in db.ContactTitle on t3.ContactTitlesID equals t6.ContactTitlesID


                     where


                    (DDLInt == 1 || t3.DivisionID == DDLInt) &&

                         //Contains

                    (
                     t3.ContactName.Contains(keyword) ||
                     t3.ContactEmail.Contains(keyword) ||
                     t3.ContactOPhone.Contains(keyword) ||
                     t3.ContactID.Equals(searchID)


                     )
                     group t3 by new
                     {
                         t3.ContactID,
                         t3.ContactName,
                         t3.ContactOPhone,
                         t3.ContactCell,
                         t3.ContactEmail,
                         t3.DivisionID,
                         t3.CategoryID,
                         t4.CategoryName,
                         t5.DivisionName,
                         t6.ContactTitlesName

                     }

                        into i

                     select new
                     {
                         i.Key.ContactID,
                         i.Key.ContactName,
                         i.Key.ContactOPhone,
                         i.Key.ContactEmail,
                         i.Key.ContactCell,
                         i.Key.CategoryName,
                         i.Key.DivisionName,
                         i.Key.CategoryID,
                         i.Key.DivisionID,
                         i.Key.ContactTitlesName
                     });


            return q.ToList<dynamic>();
        }
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1 回答 1

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使用Union()：

var contacts = from c in db.Contacts
              select new {
                           Id = c.ContactID,
                           Name = c.ContactName,
                           Phone = c.ContactOPhone,
                           ...
                           CategoryName = c.Category.CategoryName,
                           DivisionName = c.Division.DivisionName,
                           ContactTitlesName = c.ContactTitle.ContactTitlesName
                         }
var items = from t1 in db.Item
            select new {
                         Id = t1.ItemID,
                         Name = t1.ItemName,
                         Phone = t1.??, // string.Empty?
                         ... // more properties corresponding
                             // with the ones above
                         CategoryName = t1.Category.CategoryName,
                         DivisionName = t1.Division.DivisionName,
                         ContactTitlesName = string.Empty
                       }
var all = contacts.Union(items);
于 2012-12-11T08:40:42.987 回答