0

用户将在图中输入节点的数量,然后输入一个整体的“行星”名称。然后他们将输入 where 是行星的名称,以及该行星的位置数。之后,各行如下形式:……。表示位置的名称,表示和…的邻居数。是 的邻居列表。

例如: 3 Venus 4 spaceport 2 beach disco beach 1 bar bar 1 spaceport disco 1 bar Neptune 3 spaceport 1 toy-factory toy-factory 0 weapons_depot 1 Weapon_depot Binary-2 2 spaceport 1 zero-one zero-one 1 spaceport

总会有一个太空港。然后我必须从太空港开始,列出哪些节点也无法获取。这是我认为我是 Seg 错误的部分。当它试图输出节点时,它将编译然后段错误。

这是代码:

#include <iostream>
#include <map>
#include <vector>
using namespace std;
bool path(int x, int y, vector<vector<bool> > graph);

int main()
{ 
  int num_planets; 
  cin>>num_planets; 

  for (int m=0; m<num_planets; m++) 
  { 
    string planet; 
    int num_locations; 

    cin>>planet; 
    cin>>num_locations; 
    map<string, int> m_planet; 
    vector<vector<bool> > graph; 
    graph.resize(num_locations);

    for (int n=0; n<num_locations; n++) 
    { 
      graph[n].resize(num_locations); 
    } 
    for(int k=0; k<num_locations; k++) 
    { 
      for (int j=0; j<num_locations; j++) 
      {
        graph[k][j] = false; 
      } 
    } vector<vector<string> > connections;

    vector<string> places; 
    for (int o=0; o<num_locations; o++) 
    { 
      string place;

      cin>>place; 
      places.push_back(place); 
      m_planet[place] = o; 
      int edges;

      cin>>edges; 
      connections.resize(num_locations);
      connections[o].resize(edges); 

      for (int p=0; p<edges; p++) 
      { 
        string connect;
        cin>>connect; 
        connections[o][p]=connect; 
      } 
    } 

    for (int q=0; q<num_locations; q++) 
    { 
      for (int r=0; r<connections[q].size(); r++) 
      { 
        int from, to; 
        from = m_planet[places[q]]; 
        to = m_planet[connections[q][r]]; 
        graph[from][to] =true; 
      } 
    } 

    cout<<"In planet "<<planet<<":"<<endl; 

    int num_paths = 1; 
    for(int s=1; s<num_locations; s++) 
    { 
      bool route; 
      route = path(0, s, graph); 

      if(route == false) 
      { 
        cout<<places[s]<<"unreachable from the#"
          <<places[0]<<"."<<endl; 
      } 

      else 
      { 
        num_paths++; 
      } 
    } 

    if (num_paths == num_locations) 
    { 
      cout<<"All locations reachable from the#"<<places[0]<<"."<<endl; 
    } 
  } 

  return 0;
}

  bool path(int x, int y, vector<vector<bool> > graph)
  { 
    for (int m=0; m<graph[x].size(); m++) 
    { 
      if(graph[x][m] == true) 
      { 
        if (graph[x][m] == y) 
        { 
          return true; 
        } 

        else 
        {
          return path(m, y, graph); 
        } 
      } 
    } 

    return false;
  }
4

1 回答 1

0

您正在覆盖 num_locations,但试图使用它来访问这两个维度。这意味着除非用户每次都输入相同的值,否则您将遇到问题,因为其中一个维度会超出范围。

为每个维度保留单独的变量。

于 2012-12-10T23:26:22.207 回答