0

当我尝试按如下方式创建模板类时：

template <typename TList>
class Variant
{
public :
    std::string toString(); // var.toString()

    template<typename T>
    std::string toString(); // var.toStrint<int>();

    protected:
    template <typename T>
    std::string toString(T v); // internal Specialization

    template <>
    std::string toString(int v); // internal Specialization

    template <typename T>
    const T & get() 
    {
        std::size_t  type_index = TypeListNamespace::IndexOf<TList, T>::value ;

        if ( type_index == max_num_of_t  || type_index != _type_index)
            throw std::bad_cast() ;  

        void * ptr = (void*) &_variant_holder;
        T * vptr = reinterpret_cast<T *>(ptr);
        return *vptr; 
    }
};

// CPP FILE:

template <typename TList>
std::string Variant<TList>::toString ()
{
    // var.toString()
}

template<typename TList>
template<typename T>
std::string Variant<TList>::toString ()
{               
    return toString( get<T>() );  
}

template<typename TList>
template<typename T>
std::string Variant<TList>::toString (T v)
{                
    // no default toString method.
    return "";
}

template<typename TList>
template<>       
std::string Variant<TList>::toString (int v)
{                
    // Specialized toString for int values:
    return Core::Utility::formatString("%i", v );
}

.. other specializations ..

我收到以下错误：

error C2244: 'Core::Variant<TList>::toString': unable to match function definition to an existing declaration
2>          Definition
2>          'std::string Core::Variant<TList>::toString(int)'
2>          Available Deklarations
2>          'std::string Core::Variant<TList>::toString(T)'
2>          'std::string Core::Variant<TList>::toString(void)'
2>          'std::string Core::Variant<TList>::toString(void)'

当我在类定义中拥有这些特化时，都立即编译了。所以我想我的模板语法有问题。但是很难找到混合了具有专业化的类和函数模板的示例。所以我最终来到这里希望有人对我有很好的暗示。

4

2 回答 2

0

看来您不必将“模板<>”放在您的专业之上。

如果我删除它们，一切都会编译好（寻找不要在家里尝试这个）

template <typename TList>
class Variant
{
public :
    std::string toString(); // var.toString()

    template<typename T>
    std::string toString(); // var.toStrint<int>();

    protected:
    template <typename T>
    std::string toString(T v); // internal Specialization

    // DON'T TRY THIS AT HOME: template <>
    std::string toString(int v); // internal Specialization

    template <typename T>
    const T & get() 
    {
        std::size_t  type_index = TypeListNamespace::IndexOf<TList, T>::value ;

        if ( type_index == max_num_of_t  || type_index != _type_index)
            throw std::bad_cast() ;  

        void * ptr = (void*) &_variant_holder;
        T * vptr = reinterpret_cast<T *>(ptr);
        return *vptr; 
    }
};

// CPP FILE:

template <typename TList>
std::string Variant<TList>::toString ()
{
    // var.toString()
}

template<typename TList>
template<typename T>
std::string Variant<TList>::toString ()
{               
    return toString( get<T>() );  
}

template<typename TList>
template<typename T>
std::string Variant<TList>::toString (T v)
{                
    // no default toString method.
    return "";
}

template<typename TList>
// DON'T TRY THIS AT HOME: template<>       
std::string Variant<TList>::toString (int v)
{                
    // Specialized toString for int values:
    return Core::Utility::formatString("%i", v );
}

.. other specializations ..
于 2012-12-10T15:41:12.150 回答
0

正如您所说，您不需要模板<>，因为您没有专门化该功能。

你所做的是函数重载！

于 2015-09-25T11:24:57.130 回答