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我有一个异构并行编程的作业要做。代码是由教职员工编写的，我们的职责是填写由 标记的区域//@@。该代码应该使用 CUDA C 添加两个向量。我尝试了下面的解决方案，虽然程序执行没有错误，但反馈说代码的输出与预期结果不匹配。这是我添加我认为需要的代码后的代码： 

// MP 1
#include    <wb.h>

__global__ void vecAdd(float* in1, float* in2, float* out, int len) {
//@@ Insert code to implement vector addition here
int i = threadIdx.x + blockDim.x * blockIdx.x;
if (i < len ) out[i] = in1[i] + in2[i]; 
}



int main(int argc, char ** argv) {
wbArg_t args;
int inputLength;
float * hostInput1;
float * hostInput2;
float * hostOutput;
float * deviceInput1;
float * deviceInput2;
float * deviceOutput;
//@@ i added ######
int size = inputLength*sizeof(float);
//@@ ########
args = wbArg_read(argc, argv);

wbTime_start(Generic, "Importing data and creating memory on host");
hostInput1 = (float *) wbImport(wbArg_getInputFile(args, 0), &inputLength);
hostInput2 = (float *) wbImport(wbArg_getInputFile(args, 1), &inputLength);
hostOutput = (float *) malloc(inputLength * sizeof(float));

wbTime_stop(Generic, "Importing data and creating memory on host");

wbLog(TRACE, "The input length is ", inputLength);

wbTime_start(GPU, "Allocating GPU memory.");
//@@ Allocate GPU memory here

cudaMalloc((void**)&deviceInput1 , size);
cudaMalloc((void**)&deviceInput2 , size);
cudaMalloc((void**)&deviceOutput , size);
wbTime_stop(GPU, "Allocating GPU memory.");

wbTime_start(GPU, "Copying input memory to the GPU.");
//@@ Copy memory to the GPU here
cudaMemcpy(deviceInput1, hostInput1, size, cudaMemcpyHostToDevice);
cudaMemcpy(deviceInput2, hostInput2, size, cudaMemcpyHostToDevice);
wbTime_stop(GPU, "Copying input memory to the GPU.");

//@@ Initialize the grid and block dimensions here  
dim3 DimGrid((inputLength -1)/256 +1 , 1 , 1);
dim3 DimBlock(256 , 1, 1); 

wbTime_start(Compute, "Performing CUDA computation");
//@@ Launch the GPU Kernel here     
vecAdd<<<DimGrid , DimBlock>>>(deviceInput1 , deviceInput2 , deviceOutput , inputLength); 
cudaThreadSynchronize();
wbTime_stop(Compute, "Performing CUDA computation");

wbTime_start(Copy, "Copying output memory to the CPU");
//@@ Copy the GPU memory back to the CPU here
cudaMemcpy(hostOutput, deviceOutput, size , cudaMemcpyDeviceToHost);
wbTime_stop(Copy, "Copying output memory to the CPU");

wbTime_start(GPU, "Freeing GPU Memory");
//@@ Free the GPU memory here
free(deviceInput1);
free(deviceInput2);
free(deviceOutput);

wbTime_stop(GPU, "Freeing GPU Memory");

wbSolution(args, hostOutput, inputLength);

free(hostInput1);
free(hostInput2);
free(hostOutput);

return 0;
}
4

2 回答 2

2

将代码向下移动到inputLength变量获得正确值的位置。改变这个：

//@@ i added ######
int size = inputLength*sizeof(float);
//@@ ########
args = wbArg_read(argc, argv);

wbTime_start(Generic, "Importing data and creating memory on host");
hostInput1 = (float *) wbImport(wbArg_getInputFile(args, 0), &inputLength);
hostInput2 = (float *) wbImport(wbArg_getInputFile(args, 1), &inputLength);
hostOutput = (float *) malloc(inputLength * sizeof(float));

对此：

args = wbArg_read(argc, argv);

wbTime_start(Generic, "Importing data and creating memory on host");
hostInput1 = (float *) wbImport(wbArg_getInputFile(args, 0), &inputLength);
hostInput2 = (float *) wbImport(wbArg_getInputFile(args, 1), &inputLength);
hostOutput = (float *) malloc(inputLength * sizeof(float));

//@@ i added ######
int size = inputLength*sizeof(float);
//@@ ########

此外，按照 talonmies 在评论中的建议进行操作。

于 2012-12-09T17:22:55.593 回答
1

谢谢 talonmies 和 ahmad，他们都帮助我找到了对我有用的正确答案，完整的答案（谁很有趣）如下： 

// MP 1
#include    <wb.h>

__global__ void vecAdd(float* in1, float* in2, float* out, int len) {
int i = threadIdx.x + blockDim.x * blockIdx.x;
if (i < len ) out[i] = in1[i] + in2[i];
 }



int main(int argc, char ** argv) {
wbArg_t args;
int inputLength;
float * hostInput1;
float * hostInput2;
float * hostOutput;
float * deviceInput1;
float * deviceInput2;
float * deviceOutput;


args = wbArg_read(argc, argv);

wbTime_start(Generic, "Importing data and creating memory on host");
hostInput1 = (float *) wbImport(wbArg_getInputFile(args, 0), &inputLength);
hostInput2 = (float *) wbImport(wbArg_getInputFile(args, 1), &inputLength);
hostOutput = (float *) malloc(inputLength * sizeof(float));
int size = inputLength*sizeof(float);

wbTime_stop(Generic, "Importing data and creating memory on host");

wbLog(TRACE, "The input length is ", inputLength);

wbTime_start(GPU, "Allocating GPU memory.");


cudaMalloc((void**)&deviceInput1 , size);
cudaMalloc((void**)&deviceInput2 , size);
cudaMalloc((void**)&deviceOutput , size);
wbTime_stop(GPU, "Allocating GPU memory.");

wbTime_start(GPU, "Copying input memory to the GPU.");

cudaMemcpy(deviceInput1, hostInput1, size, cudaMemcpyHostToDevice);
cudaMemcpy(deviceInput2, hostInput2, size, cudaMemcpyHostToDevice);
wbTime_stop(GPU, "Copying input memory to the GPU.");


dim3 DimGrid((inputLength -1)/256 +1 , 1 , 1);
dim3 DimBlock(256 , 1, 1); 

wbTime_start(Compute, "Performing CUDA computation");
//@@ Launch the GPU Kernel 

vecAdd<<<DimGrid , DimBlock>>>(deviceInput1 , deviceInput2 , deviceOutput ,  inputLength);

cudaThreadSynchronize();
wbTime_stop(Compute, "Performing CUDA computation");

wbTime_start(Copy, "Copying output memory to the CPU");
//@@ Copy the GPU memory back to the CPU 
cudaMemcpy(hostOutput, deviceOutput, size , cudaMemcpyDeviceToHost);
wbTime_stop(Copy, "Copying output memory to the CPU");

wbTime_start(GPU, "Freeing GPU Memory");
//@@ Free the GPU memory 
cudaFree(deviceInput1);
cudaFree(deviceInput2);
cudaFree(deviceOutput);

wbTime_stop(GPU, "Freeing GPU Memory");

wbSolution(args, hostOutput, inputLength);

free(hostInput1);
free(hostInput2);
free(hostOutput);

return 0;
}
于 2012-12-12T18:38:30.487 回答