我有 5 张桌子。我需要从一个表中选择 4 个最近的帖子,并在四个单独的变量中获取这些帖子的 ID,以用于来自其他表的查询:
SELECT user FROM table1 WHERE subcategory = "$input" ORDER BY id DESC LIMIT 4;
所以我有我需要的东西。现在,我如何将这四个用户 ID 结果分配给新变量,以便在同一页面上的未来查询中使用。
我需要像这样存储它:
$user1 = "Sue";
$user2 = "Dave";
$user3 = "Alicia";
$user4 = "Tim";
所以我可以这样使用它:
SELECT * FROM table2 WHERE user = $user1;
SELECT * FROM table2 WHERE user = $user2;
SELECT * FROM table2 WHERE user = $user3;
SELECT * FROM table2 WHERE user = $user4;
不要混淆这个问题,但是:最终目标是拥有多行但只有四列,其中行中的所有数据都由顶行中的 USER 排序。请务必注意,因为每组行都由其下方数据中包含的内容的描述分隔。这些只是简单的直列。像这样的东西:
Sue Dave Alicia Tim
Sue Profile Dave Profile Alicia Profile Tim Profile
>>Answers to questions about work:
Sue Income Dave Income Alicia Income Tim Income
Sue Years Dave Years Alicia Years Tim Years
>>Answers to questions about school:
Sue Degree Dave Degree Alicia Degree Tim Degree
Sue Schools Dave Schools Alicia Schools Tim Schools
>>Answers to questions about life:
Sue Born Dave Born Alicia Born Tim Born
Sue Parents Dave Parents Alicia Parents Tim Parents
如果我可以将 id 结果读入单独的变量,那么对于每个部分(问题),我可以执行以下操作:
SELECT * FROM income WHERE user = "Sue";
SELECT * FROM income WHERE user = "Dave";
SELECT * FROM income WHERE user = "Alicia";
SELECT * FROM income WHERE user = "Tim";
SELECT * FROM degree WHERE user = "Sue";
SELECT * FROM degree WHERE user = "Dave";
SELECT * FROM degree WHERE user = "Alicia";
SELECT * FROM degree WHERE user = "Tim";