6

这个问题是关于 Unity Container 的，但我想它适用于任何依赖容器。

我有两个具有循环依赖关系的类：

class FirstClass
{
    [Dependency]
    public SecondClass Second { get; set; }
}

class SecondClass
{
    public readonly FirstClass First;

    public SecondClass(FirstClass first)
    {
        First = first;
    }
}

从技术上讲，如果将它们视为单例，则可以为它们实例化并正确注入依赖项：

var firstObj = new FirstClass();
var secondObj = new SecondClass(firstObj);
firstObj.Second = secondObj;

当我尝试对 Unity 执行相同操作时，我得到 StackOverflowException：

var container = new UnityContainer();
container.RegisterType<FirstClass>(new ContainerControlledLifetimeManager());
container.RegisterType<SecondClass>(new ContainerControlledLifetimeManager());

var first = container.Resolve<FirstClass>(); // StackOverflowException here!
var second = container.Resolve<SecondClass>(); // StackOverflowException here too!

我了解 Unity 试图保护我免于使用部分初始化的对象，但我希望将此保护作为一种选择，而不是一种义务。

问题：当前行为是否可禁用？

4

3 回答 3

5

我认为你根本不能使用统一的循环依赖。

请参阅：http: //msdn.microsoft.com/en-us/library/cc440934.aspx

于 2009-09-04T07:04:01.910 回答
2

解决此问题的一种方法是对其中一个类的依赖项使用延迟加载：

[TestFixture]
public class CircularUnityTest
{
    IUnityContainer container;

    [SetUp]
    public void SetUp()
    {
        container = new UnityContainer();
        container.RegisterType(typeof(ILazy<>), typeof(Lazy<>));
        container.RegisterType<FirstClass>(new ContainerControlledLifetimeManager());
        container.RegisterType<SecondClass>(new ContainerControlledLifetimeManager());
    }

    [Test]
    public void CanResolveFirstClass()
    {
        var first = container.Resolve<FirstClass>();
        Assert.IsNotNull(first);
    }

    [Test]
    public void CanResolveSecondClass()
    {
        var second = container.Resolve<SecondClass>();
        Assert.IsNotNull(second);
    }

    [Test]
    public void CanGetFirstFromSecond()
    {
        var second = container.Resolve<SecondClass>();
        Assert.IsNotNull(second.First);
    }
}

class FirstClass 
{
    [Dependency]
    public SecondClass Second { get; set; }
}

class SecondClass
{
    private readonly ILazy<FirstClass> lazyFirst;

    public FirstClass First { get { return lazyFirst.Resolve(); } }

    public SecondClass(ILazy<FirstClass> lazyFirst)
    {
        this.lazyFirst = lazyFirst;
    }
}

public interface ILazy<T>
{
    T Resolve();
}

public class Lazy<T> : ILazy<T>
{
    IUnityContainer container;

    public Lazy(IUnityContainer container)
    {
        this.container = container;
    }

    public T Resolve()
    {
        return container.Resolve<T>();
    }
}
于 2009-09-17T09:25:33.310 回答
1

您可以使用 RegisterInstance 而不是 RegisterType 来实现您的目标。它的行为就像单例一样 - 每次调用 Resolve 时都会使用相同的实例。看看这个例子：

class FirstClass
{
    [Dependency]
    public SecondClass Second { get; set; }
}

class SecondClass
{
    public readonly FirstClass First;

    public SecondClass(FirstClass first)
    {
        First = first;
    }
}

class Program
{
    static void Main(string[] args)
    {
        IUnityContainer container = new UnityContainer();
        var firstObj = new FirstClass();

        var secondObj = new SecondClass(firstObj);
        firstObj.Second = secondObj;

        // Register instance instead of type!!!
        container.RegisterInstance<FirstClass>(firstObj);
        container.RegisterType<SecondClass>();

        var first = container.Resolve<FirstClass>();
        var second = container.Resolve<SecondClass>(); 
    }
}

干杯，

帕维尔

于 2009-09-18T11:09:53.050 回答