如何从单个 html 表单发布用户名、密码和多个二进制文件并使用 php 处理?我不允许使用ajax。
lajos
问问题
7545 次
2 回答
6
首先在 PHP.net 上查看这些页面
但是为了让你开始,这里有几个存根文件。
上传表单.html
<html>
<body>
<form action="processStuff.php" enctype="multipart/form-data" method="POST">
username: <input type="text" name="username" />
password: <input type="password" name="password" />
<p>
<input type="file" name="uploadFile[]" /><br />
<input type="file" name="uploadFile[]" /><br />
<input type="file" name="uploadFile[]" /><br />
<!-- Add as many of these as you want -->
</p>
<p>
<input type="submit" />
</p>
</form>
</body>
</html>
processStuff.php
<pre>
<?php
echo '<h2>Username & password</h2>'
echo "Username: {$_POST['username']}\nPassword: {$_POST['password']}";
echo '<hr />';
echo '<h2>Uploaded files</h2>'
foreach($_FILES['uploadFile']['tmp_name'] as $i => $tempUploadPath) {
if (empty($tempUploadPath)) {
// this <input type="file" /> was "blank"... no file selected
} else {
// a file was uploaded
echo '<strong>A file named "', $_FILES['uploadFile']['name'][$i], "\" was uploaded</strong>\n";
echo "\ttemporarily stored at: ", $tempUploadPath, "\n";
echo "\tmime type: ", $_FILES['uploadFile']['type'][$i], "\n";
echo "\tsize: ", $_FILES['uploadFile']['size'][$i], " bytes\n";
echo "\terror code",
((empty($_FILES['uploadFile']['size'][$i])
? '<em>no errror</em>'
: $_FILES['uploadFile']['size'][$i])),
"\n\n";
// do something useful with the uploaded file
// access it via $tempUploadPath and use move_uploaded_file() to move
// it out of the temp path before you manipulate it in any way!!!!!
// see http://us3.php.net/features.file-upload
// and http://us3.php.net/manual/en/function.move-uploaded-file.php
}
}
?>
</pre>
HTML 文件展示了如何设置enctype
第二<form>
个表单,展示如何访问提交的用户名和密码,最后如何循环遍历每个上传的文件。
如前所述,您必须尽快移动文件。它们被上传到临时位置,除非您处理它们,否则系统将删除它们。所以先把它们移到某个地方,然后用它们做任何你需要的事情。
希望这有帮助
阿林
于 2008-09-26T05:28:00.000 回答
1
您应该使用$_FILES
超全局和move_uploaded_file()
函数来查看哪些文件已成功上传,并将它们移动到最终位置,以防万一。
超$_POST
全局将包含提交的用户名和密码。
于 2008-09-26T04:16:07.177 回答