-3

我从文本文件中输出以下内容：

================================================

guideMenuSuite.mts:
[monkeytalk:run] MonkeyTalk v1.0.11.beta5c_473 - 2012-07-18 11:38:51 MDT - Copyright 2012 Gorilla Logic, Inc. - www.gorillalogic.com
[monkeytalk:run] running suite guideMenuSuite.mts...
[monkeytalk:run] BCOKAS127271: -start suite (1 test)
[monkeytalk:run] BCOKAS127271:   1 : guide_menu.mt
[monkeytalk:run] BCOKAS127271:   -> OK
[monkeytalk:run] BCOKAS127271: -end suite
[monkeytalk:run] result: OK
[monkeytalk:run] ...done

=================================================

在 Java 中，我需要： 1）解析设备序列号的输出（在这种情况下为 BCOKAS127271 ......它会根据正在测试的设备而变化）。2) 获取->（本例中为-> OK）之后的测试状态结果。

我尝试使用拆分，但数据一直为空...

任何建议将不胜感激。

这是我的代码：

代码

while ((strLine = br.readLine()) != null) 
                {
                    maintextarea.append(strLine + "\n");
                    System.out.println(strLine);
                    System.out.flush();
                    maintextarea.append(selectedSerial);
                    delims = "[ \\->]+";
                    //String[] tokens = strLine.split(delims);
                    //String[] tokens = strLine.substring(prefix.length()).split(delims);

                    String noprefixStr = strLine.substring(strLine.indexOf(prefix) + prefix.length());
                    String[] tokens = noprefixStr.split(delims);

                    //for (String t: tokens)
                    {
                        //System.out.println(t);

                            if (tokens.toString().contains("ERROR"))
                            {
                                testStatus = "ERROR";
                                maintextarea.append("\n" + selectedValue + " " + selectedSerial + " = " + testStatus + "\n");
                                System.out.println(selectedValue + " " + selectedSerial + " = " + testStatus);
                                System.out.flush();
                            }

                            else if (tokens.toString().contains("FAILURE"))
                            {
                                testStatus = "FAILED";
                                maintextarea.append("\n" + selectedValue + " " + selectedSerial + " = " + testStatus + "\n");
                                System.out.println(selectedValue + " " + selectedSerial + " = " + testStatus);
                                System.out.flush();
                            }

                            else if (tokens.toString().contains("OK"))
                            {
                                testStatus = "PASSED";
                                maintextarea.append("\n" + selectedValue + " " + selectedSerial + " = " + testStatus + "\n");
                                System.out.println(selectedValue + " " + selectedSerial + " = " + testStatus);
                                System.out.flush();
                            }

                            else
                            {
                                testStatus = "N/A";
                                maintextarea.append("\n" + selectedValue + " " + selectedSerial + " = " + testStatus + "\n");
                                System.out.println(selectedValue + " " + selectedSerial + " = " + testStatus);
                                System.out.flush();
                            }

                    }


                }


                br.close();

==================================================== ==========

更新：

我根据从这个小组收到的所有意见找到了我的解决方案！我最终使它变得非常简单并解析输出文件以获取表达式，然后基于该设置一个变量来传递或失败或错误。

这是我使用的基本代码：

try 
        {
            BufferedReader br = new BufferedReader(new InputStreamReader(new DataInputStream(new FileInputStream("/home/ironmantis7x/Documents/TWC_test/MT_test_runner_output.txt"))));
            String strLine;
            while ((strLine = br.readLine()) != null)
            {
                if (strLine.contains("-> OK"))
                {
                    testStatus = "Pass";
                    System.out.println("Test Result = " + testStatus);
                }

            }
        } 

        catch (FileNotFoundException ex) 
        {
            Logger.getLogger(parseFile.class.getName()).log(Level.SEVERE, null, ex);
        }

对不起，我花了这么长时间才回复你们并说谢谢！

铁螳螂7x

4

1 回答 1

1

您可以使用正则表达式：

import java.util.Pattern
import java.util.Matcher

Pattern status = Pattern.compile("\\[.*] \\w+:\\s+-> (\w+).*");

...

你可以在这里学习如何做

于 2012-12-07T22:54:04.480 回答