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我找到并修改了简单的代码，以使用 openweather 和 json 格式在 Python 中获取天气状况。但我有一个问题——我怎么能说城市不正确呢？

我的意思是，即使我经过一个错误的、不存在的城市，阅读也总会给出答案（没有像“空响应”之类的东西）。

请参阅下面的代码以了解我在说什么：

#!/usr/bin/python
# -*- coding: utf-8 -*-
import urllib2, json

city = "etre4t5r5e4re" # the city name is incorrent
url = "http://openweathermap.org/data/2.1/forecast/city?q="
url += city
try :
    request = urllib2.Request(url)
    response = urllib2.urlopen(request)
except urllib2.HTTPError, e:
    info = wx.MessageBox(u"Internet connection error", u"Error", wx.OK | wx.ICON_ERROR)
except urllib2.URLError, e:
    info = wx.MessageBox(u"Internet connection error", u"Error", wx.OK | wx.ICON_ERROR)
except httplib.HTTPException, e:
    info = wx.MessageBox(u"Internet connection error", u"Error", wx.OK | wx.ICON_ERROR)
except Exception:
    info = wx.MessageBox(u"Error", u"Error", wx.OK | wx.ICON_ERROR)
weather = response.read()

if __name__ == '__main__':
    print(weather) # it will show weather but thats not what I want for non-existing city!
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1 回答 1

1

当请求的城市不存在时，会有一个经常性 ID，您可以基于您的代码，或者提出第二个请求。我已经解释了我会使用的两种解决方案。

#!/usr/bin/python

import urllib2, json

city = "etre4t5r5e4re"
root = "http://openweathermap.org/data/2.1/forecast/city?q=%s"
url  = root % city

response = urllib2.urlopen(url)
j = json.load(response)

# Solution 1
if j.get('url', '').split('/')[-1] == '7284885':
    print " ! This city seems to be THE Unknown city"

# Solution 2
if 'No station' in urllib2.urlopen(j.get('url')).read():
    print " ! Again.. This city seems to be THE Unknown city"
于 2012-12-07T17:15:34.567 回答