sql - 找出时差并将时差分组

Question

SELECT
yt1.[timestamp] AS StartTime,
MIN(yt2.[timestamp]) AS EndTime,
DATEDIFF(s, yt1.[timestamp], MIN(yt2.[timestamp])) AS DifferenceInSeconds
FROM
yourTable yt1
LEFT JOIN yt2 ON yt1.[timestamp] < yt2.[timestamp]
WHERE
yt1.Col1 IS NULL
OR yt1.Col2 IS NULL
...
OR yt1.Col20 IS NULL
OR yt2.Col1 IS NULL
...
OR yt2.Col20 IS NULL 
GROUP BY yt1.[timestamp]

在同一个查询中，当前输出就像

18-05-2012 20:07
18-05-2012 20:17
18-05-2012 20:27
18-05-2012 20:37 

等有 10 分钟的间隔，连续的间隔我们应该看到 18-05-2012 20:07 作为开始时间和 18-05-2012 20:37 作为结束时间和间隔 40 分钟。你能帮忙吗