1

我有一个没有 GPS 模块的设备。有没有办法在不使用 Android 中的 GPS 模块的情况下获得 Lat Lon 值。

嘿，选民们，你能解释一下这个问题有什么问题吗？如果您对该问题有答案，请尝试理解这些问题。

4

3 回答 3

5

如果您的设备没有 GPS，那么您也可以使用 Network_Provider 获取纬度和经度，使用下面的代码使用 Network_Provider 获取纬度和经度，它将解决您的问题。

LocationManager lm = (LocationManager) GlobalApplication
            .getAppContext().getSystemService(Context.LOCATION_SERVICE);

Location location = lm
            .getLastKnownLocation(LocationManager.NETWORK_PROVIDER);

if(location != null){
    double latitude = location.getLatitude();
    double longitude = location.getLongitude();
}
于 2012-12-07T10:39:37.183 回答
5

只需将 Java 类放在您的包中即可。

我的位置.java

    import java.util.Timer;
import java.util.TimerTask;
import android.content.Context;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;

public class MyLocation {
    Timer timer1;
    LocationManager lm;
    LocationResult locationResult;
    boolean gps_enabled=false;
    boolean network_enabled=false;

    public boolean getLocation(Context context, LocationResult result)
    {
        //I use LocationResult callback class to pass location value from MyLocation to user code.
        locationResult=result;
        if(lm==null)
            lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);

        //exceptions will be thrown if provider is not permitted.
        try
        {
            gps_enabled=lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
        }
        catch(Exception ex)
        {
            ex.printStackTrace();
        }
        try
        {
            network_enabled=lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
        }
        catch(Exception ex)
        {
            ex.printStackTrace();
        }

        //don't start listeners if no provider is enabled
        if(!gps_enabled && !network_enabled)
            return false;

        if(gps_enabled)
            lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0, locationListenerGps);
        if(network_enabled)
            lm.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0, locationListenerNetwork);
        timer1=new Timer();
        timer1.schedule(new GetLastLocation(), 20000);
        return true;
    }

    LocationListener locationListenerGps = new LocationListener() 
    {
        public void onLocationChanged(Location location) 
        {
            timer1.cancel();
            locationResult.gotLocation(location);



          //  lm.removeUpdates(this);
            //lm.removeUpdates(locationListenerNetwork);
        }
        public void onProviderDisabled(String provider) {}
        public void onProviderEnabled(String provider) {}
        public void onStatusChanged(String provider, int status, Bundle extras) {}
    };

    LocationListener locationListenerNetwork = new LocationListener()
    {
        public void onLocationChanged(Location location) 
        {
            timer1.cancel();
            locationResult.gotLocation(location);
           // lm.removeUpdates(this);
         //   lm.removeUpdates(locationListenerGps);
        }
        public void onProviderDisabled(String provider) {}
        public void onProviderEnabled(String provider) {}
        public void onStatusChanged(String provider, int status, Bundle extras) {}
    };

    class GetLastLocation extends TimerTask 
    {
        @Override
        public void run() {
             //lm.removeUpdates(locationListenerGps);
             //lm.removeUpdates(locationListenerNetwork);

             Location net_loc=null, gps_loc=null;
             if(gps_enabled)
                 gps_loc=lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);
             if(network_enabled)
                 net_loc=lm.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);

             //if there are both values use the latest one
             if(gps_loc!=null && net_loc!=null){
                 if(gps_loc.getTime()>net_loc.getTime())
                     locationResult.gotLocation(gps_loc);
                 else
                     locationResult.gotLocation(net_loc);
                 return;
             }

             if(gps_loc!=null){
                 locationResult.gotLocation(gps_loc);
                 return;
             }
             if(net_loc!=null){
                 locationResult.gotLocation(net_loc);
                 return;
             }
             locationResult.gotLocation(null);
        }
    }

    public static abstract class LocationResult
    {
        public abstract void gotLocation(Location location);
    }
}

现在，在您的活动中，您可以找到如下代码所示的位置：

    public static Location loc;

        @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.splash_layout);

        // to Find the Location 
        LocationResult locationResult = new LocationResult(){
            @Override
            public void gotLocation(final Location location){
                loc=location;
                System.out.println("Latitude: "+loc.getLatitude());
                System.out.println("Longitude: "+loc.getLongitude());
            }
        };

        MyLocation myLocation = new MyLocation();
    myLocation.getLocation(SplashActivity.this, locationResult);
    }
}

使用上面的代码，您不必在设备中使用 GPS。它将自动检查最佳可用的位置管理器并根据它找到位置。

它还需要 AndroidManifest.xml 文件中的一些权限。

希望它会帮助你。

于 2012-12-07T10:43:58.390 回答
2 
    Location location =myManager.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);
    latPoint=location.getLatitude();
    lngPoint=location.getLongitude();

希望这会帮助你。在这里，我们使用不使用 GPS 的网络提供商获取纬度和经度。这就是你想要的。

于 2012-12-07T10:39:11.627 回答