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我想问一些关于查询的问题。我有一个 mysql 表，想生成一个有点复杂的表。

假设我有这 3 张桌子..

Ship_terms

id |  Name        | Keterangan
-------------------------
1  | Installation | Instalasi
2  | Delivery     | Pengiriman

Shipp_list

id | tipeShipp | namaShipp | Keterangan
----------------------------------------
1  | 1         | KMA       | Bla Bla Bla
2  | 1         | MTECH     | Bla Bla Bla
3  | 2         | JNE       | Bli Bli BLi

Shipp_price

id | idShipp | kota    | price
_______________________________
1  | 1       | Jakarta | 0
2  | 2       | Jakarta | 0
3  | 3       | Bandung | 10000
4  | 3       | Jakarta | 5000

注意： ship_terms.id = shipp_list.tipeShipp，shipp_price.idShipp = shipp_list.id

而我真正想要的是..查询的结果（使用'kota = jakarta'）是这样的......

-----------------
INSTALLATION
-----------------
1. KMA - 0
2. MTECH - 0
-----------------
DELIVERY
-----------------
1. JNE - 5000

这里有人可以帮助我吗？？谢谢

*更新

这是我的查询：

{
    /* Jika tersedia, lakukan pengambilan data */

    /* Hitung berat */
    $queryBerat = "SELECT SUM(berat)as berat FROM tmp_detail_jual WHERE username = '$_SESSION[uname]'";
    $run = $db->query($queryBerat);
    $data_berat = $run->fetch(PDO::FETCH_ASSOC);
    $berat = $data_berat[berat]*$data_berat[jumBarang];
    $beratTot = ceil($berat);
    /* ambil data shipping */
     while($data_table = $cek->fetch(PDO::FETCH_ASSOC)){
         $idShipp = $data_table[idShipp];
         $harga = $data_table[price];
         /* ambil nama kurir */
         $querynama = "SELECT * FROM shipp_list where id='$idShipp'";
         $getNama = $db->query($querynama);
         while($namaShipp = $getNama->fetch(PDO::FETCH_ASSOC)){
             $nama = $namaShipp[namaShipp];
             $keterangan = $namaShipp[keterangan];
             $tipeShipp = $namaShipp[tipeShipp];
             $idShippList = $namaShipp[id];
             /* Cek tipe kurir */
             $queryjenis = "SELECT * FROM ship_terms where id='$tipeShipp'";
             $getJenis = $db->query($queryjenis);
             while($namaTerms = $getJenis->fetch(PDO::FETCH_ASSOC)){
                 $namaTerm = $namaTerms[name];
                 $keterangan = $namaTerms[keterangan];

                 /* Echo datanya */
                  echo '<br>'.$namaTerm.'<br>';
                  echo $nama.' - '.$harga*$beratTot;



             }
         }
     }
}

但我得到了这样的结果

-----------------
INSTALLATION
-----------------
KMA - 0
-----------------
INSTALLATION
-----------------
MTECH - 0
-----------------
DELIVERY
-----------------
JNE - 5000

你能给我一个建议吗，所以我的查询结果会是这样的

-----------------
INSTALLATION
-----------------
1. KMA - 0
2. MTECH - 0
-----------------
DELIVERY
-----------------
1. JNE - 5000
4

2 回答 2

0

尝试安装，

SELECT namaShipp, price
FROM Shipp_list
INNER JOIN Shipp_price ON shipp_list.id = shipp_price.idShipp
WHERE kota = 'jakarta' AND tipeShipp = 1

AND交货

SELECT namaShipp, price
FROM Shipp_list
INNER JOIN Shipp_price ON shipp_list.id = shipp_price.idShipp
WHERE kota = 'jakarta' AND tipeShipp = 2
于 2012-12-07T06:49:59.107 回答
0

尝试这个：

SELECT sl.id,  st.name, sl.namaShipp, sp.price 
FROM Shipp_list sl 
INNER JOIN Ship_terms st ON sl.tipeShipp = st.id 
LEFT JOIN Shipp_price sp ON sl.id = sp.idShipp
于 2012-12-07T06:56:48.407 回答