正如标题所述,我创建了一个 D3 线/面积图,我发现很难让图形的宽度保持不变,这取决于我给它渲染的数据量,它会缩放图形的宽度因此,但我不确定如何让它保持在一个恒定的宽度,不管给定的数据量是多少,这是我想要实现的。
我想这与 x 和 y 坐标的缩放有关,但我现在被困住了,似乎无法弄清楚它为什么这样做。
这是我到目前为止的代码,
//dimensions and margins
var width = 625,
height = 350,
margin = 5,
// get the svg and set it's width/height
svg = d3.select("#main")
.attr("width", width)
.attr("height", height);
//initialize the graph
init([
[12345,42345,32345,22345,72345,62345,32345,92345,52345,22345],
[1234,4234,3234,2234,7234,6234,3234,9234,5234,2234]
]);
$("button").live('click', function(){
var id = $(this).attr("id");
if(id == "one"){
updateGraph([
[52345,32345,12345,22345,62345,72345,92345,32345,22345,22345,52345,32345,12345,22345,62345,72345,92345,32345,22345,22345,52345,32345,12345,22345,62345,72345,92345,32345,22345,22345],
[4234,12345,2234,32345,6234,7234,9234,3234,2234,2234,4234,1234,2234,3234,6234,7234,9234,3234,2234,2234,4234,1234,2234,3234,6234,7234,9234,3234,2234,2234]
]);
}else if(id == "two"){
updateGraph([
[12345,42345,32345,22345,72345,62345,32345,92345,52345,22345,12345,42345,32345,22345,72345,62345,32345,92345,52345,22345,12345,42345,32345,22345,72345],
[1234,2345,3234,2234,7234,6234,3234,9234,5234,2234,1234,4234,3234,2234,7234,6234,3234,9234,5234,2234,1234,4234,3234,2234,7234]
]);
}
});
function init(data){
var x = d3.scale.linear()
.domain([0,data[0].length])
.range([margin, width-margin]),
y = d3.scale.linear()
.domain([0,d3.max(data[0])])
.range([height-margin, margin]),
/* line path generator */
line = d3.svg.line().interpolate('monotone')
.x(function(d,i) { return x(i); })
.y(function(d) { return y(d); }),
/* area path generator */
area = d3.svg.area().interpolate('monotone')
.x(line.x())
.y1(line.y())
.y0(y(0)),
groups = svg.selectAll("g")
.data(data)
.enter()
.append("g");
svg.select("g")
.selectAll("circle")
.data(data[0])
.enter()
.append("circle")
.attr("class", "dot")
.attr("cx", line.x())
.attr("cy", line.y())
.attr("r", 4);
/* add the areas */
groups.append("path")
.attr("class", "area")
.attr("d",area)
.style("fill", function(d,i) { return (i == 0 ? "steelblue" : "red" ); });
/* add the lines */
groups.append("path")
.attr("class", "line")
.attr("d", line);
}
function updateGraph(data){
var x = d3.scale.linear()
.domain([0,data[0].length])
.range([margin, width-margin]),
y = d3.scale.linear()
.domain([0,d3.max(data[0])])
.range([height-margin, margin]),
/* line path generator */
line = d3.svg.line().interpolate('monotone')
.x(function(d,i) { return x(i); })
.y(function(d) { return y(d); }),
/* area path generator */
area = d3.svg.area().interpolate('monotone')
.x(line.x())
.y1(line.y())
.y0(y(0));
groups = svg.selectAll("g")
.data(data),
circles = svg.select("g")
.selectAll("circle");
circles.data(data[0])
.exit().remove();
circles.data(data[0])
.enter().append("circle")
.attr("class", "dot")
.attr("cx", line.x())
.attr("cy", line.y())
.attr("r", 4);
/* animate circles */
circles.data(data[0])
.transition()
.duration(1000)
.attr("cx", line.x())
.attr("cy", line.y());
/* animate the lines */
groups.select('.line')
.transition()
.duration(1000)
.attr("d",line);
/* animate the areas */
groups.select('.area')
.transition()
.duration(1000)
.attr("d",area);
}
</p>
以及小提琴http://jsfiddle.net/JL33M/
谢谢!