1

我有一张像这样的桌子:

id  ip
--  -----------
1   192.168.2.1

并且需要得到如下结果:

id  ip           A    B    C    D
--  -----------  ---  ---  ---  ---
1   192.168.2.1  192  168  2    1

可行吗?

4

1 回答 1

3
SELECT `id`, `ip`,
    SUBSTRING_INDEX( `ip` , '.', 1 ) AS a,
    SUBSTRING_INDEX(SUBSTRING_INDEX( `ip` , '.', 2 ),'.',-1) AS b,
    SUBSTRING_INDEX(SUBSTRING_INDEX( `ip` , '.', -2 ),'.',1) AS c,
    SUBSTRING_INDEX( `ip` , '.', -1 ) AS d
FROM unicorns

资源

例子

SET @ip = '192.168.1.1';

SELECT @ip,
    SUBSTRING_INDEX( @ip , '.', 1 ) AS a,
    SUBSTRING_INDEX(SUBSTRING_INDEX( @ip , '.', 2 ),'.',-1) AS b,
    SUBSTRING_INDEX(SUBSTRING_INDEX( @ip , '.', -2 ),'.',1) AS c,
    SUBSTRING_INDEX( @ip , '.', -1 ) AS d

结果

| @IP | 一个 | 乙| C | D |
----------------------------------
| 192.168.1.1 | 192 | 168 | 1 | 1 |
于 2012-12-06T19:00:47.490 回答