我敢肯定这应该很简单——但我在上下文方面遇到了麻烦!
示例 XML:
<test>
<HtlSeg>
<SegNum>1</SegNum>
<StartDt>20130624</StartDt>
<NumNights>2</NumNights>
<Conf>28618</Conf>
</HtlSeg>
<CommentInfo>
<CommentNum>1</CommentNum>
<SegMatch>28618</SegMatch>
<Comment>THIS IS A TEST</Comment>
</CommentInfo>
<CommentInfo>
<CommentNum>2</CommentNum>
<SegMatch>28618</SegMatch>
<Comment>HOTEL BOOKED</Comment>
</CommentInfo>
<CommentInfo>
<CommentNum>3</CommentNum>
<SegMatch>28618</SegMatch>
<Comment>NON REFUNDABLE</Comment>
</CommentInfo>
<CommentInfo>
<CommentNum>4</CommentNum>
<SegMatch>1459</SegMatch>
<Comment>CAR BOOKING</Comment>
</CommentInfo>
<CommentInfo>
<CommentNum>5</CommentNum>
<SegMatch>1528</SegMatch>
<Comment>AIR BOOKING</Comment>
</CommentInfo>
<CommentInfo>
<CommentNum>6</CommentNum>
<SegMatch>1528</SegMatch>
<Comment>NON REFUNDABLE</Comment>
</CommentInfo>
<CommentInfo>
<CommentNum>7</CommentNum>
<SegMatch>1528</SegMatch>
<Comment>NON SMOKING</Comment>
</CommentInfo>
在 XSLT 中,我的上下文节点是<HtlSeg>
.
我正在尝试访问<CommentInfo>
节点<SegMatch>
等于<Conf>
.<HotelSeg>
我试过的xpath是following-sibling::CommentInfo[SegMatch=Conf]/Comment
但是不返回任何东西。我认为在 xpath 中使用“Conf”时我已经失去了上下文<HotelSeg>
- 但我确信这在简单的 Xpath 中必须是可能的,而无需声明变量?
干杯达伦