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我正在使用 EF 代码优先方法和流利的 api。我的申请中有一个注册表单,在其中注册候选人可以从下拉列表中选择多个选项(对注册表单上的下拉列表感兴趣),其中包含一组预定义的选项(将来可能会增加,但机会非常少)。当用户提交表单时,我想将此记录保存到数据库中。所以我创建了以下实体。

将保存注册候选人信息的参与者班级

public class Participant
    {
        public Participant()
        {
            Interests = new Collection<Interest>();
        }
        [Key]
        public int Id { get; set; }
        [DisplayName("First Name")]
        [StringLength(50, ErrorMessage = "First name cannot be more than 50 characters")]
        [Required(ErrorMessage = "You must fill in first name")]
        public string FirstName { get; set; }

        [DisplayName("Last Name")]
        [StringLength(50, ErrorMessage = "Last name cannot be more than 50 characters")]
        [Required(ErrorMessage = "You must fill in last name")]
        public string LastName { get; set; }

        [Required(ErrorMessage = "You must indicate your full birthday")]
        [DisplayName("Birthday")]
        [DataType(DataType.DateTime)]
        public DateTime BirthDate { get; set; }

        [DisplayName("Gender")]
        [Required(ErrorMessage = "You must select gender")]
        public int Gender { get; set; }

        public string Address { get; set; }

        public int CountryId { get; set; }
        public Country Country { get; set; }

        [DisplayName("Zip code")]
        [StringLength(10, ErrorMessage = "Zip code cannot be more than 10 characters")]
        public string ZipCode { get; set; }

        public string Mobile { get; set; }

        public string PhotoUrl { get; set; }

        public int UserId { get; set; }
        public User User { get; set; }

        public virtual ICollection<Interest> Interests { get; set; }
}

注册表格上的“感兴趣”下拉列表中的兴趣类 *用户可以从“感兴趣”下拉列表中选择多个选项*

public class Interest
    {
        public Interest()
        {
            Participants = new Collection<Participant>();
        }
        public int Id { get; set; }
        public string InterestName { get; set; }
        public virtual ICollection<Participant> Participants { get; set; }
    }

为了保持每个参与者的兴趣,我在 DB 中使用以下模式创建了一个 ParticipantInterests 表。 ParticipantInterests Id (PK) ParticipantId(来自 Participants 表的 FK) InterestId(FK Interests 表)

public virtual ICollection<Participant> Participants { get; set; }在兴趣模型中添加了

public virtual ICollection<Interest> Interests { get; set; } in Participant model to form Many-To-Many association.

我的数据上下文类如下

public class STNDataContext : DbContext
    {
        public DbSet<User> Users { get; set; }
        public DbSet<Participant> Participants { get; set; }
        public DbSet<Country> Countries { get; set; }
        public DbSet<Interest> Interests { get; set; }
        public DbSet<Role> Roles { get; set; }
        public DbSet<SecurityQuestion> SecurityQuestions { get; set; }

        public DbSet<Tour> Tours { get; set; }
        protected override void OnModelCreating(DbModelBuilder modelBuilder)
        {
            modelBuilder.Entity<Participant>().
                HasMany(p => p.Interests).
                WithMany().
                Map(
                    m =>
                    {
                        m.ToTable("ParticipantInterests");
                        m.MapLeftKey("ParticipantId");
                        m.MapRightKey("InterestId");
                    });
            modelBuilder.Entity<User>().HasRequired(u => u.Role);
            modelBuilder.Entity<Participant>().HasRequired(p => p.Country);
            modelBuilder.Entity<Participant>().HasRequired(p => p.Interests);
        }


        public virtual void Commit()
        {
            base.SaveChanges();
        }
    }

控制器动作代码

public virtual ActionResult Register(StudentRegisterViewModel studentRegisterViewModel)
        {
if (ModelState.IsValid)
            {
                if (_userService.IsUserExists(studentRegisterViewModel.Participant.User) == false)
                {
                    studentRegisterViewModel.Participant.User.Username = studentRegisterViewModel.Username;
                    studentRegisterViewModel.Participant.User.Email = studentRegisterViewModel.Email;
                    studentRegisterViewModel.Participant.User.DateCreated = DateTime.Now;
                    studentRegisterViewModel.Participant.User.Id = 3;
                    studentRegisterViewModel.Participant.User.IsApproved = false;
                    studentRegisterViewModel.Participant.User.RoleId = 2;
                    studentRegisterViewModel.Participant.CountryId = 1;
                    foreach (var interestItem in studentRegisterViewModel.SelectedInterests)
                    {
                        var interest = new Interest { Id = interestItem};
                        studentRegisterViewModel.Participant.Interests.Add(interest);
                    }

                    _participantService.CreatParticipant(studentRegisterViewModel.Participant);

                }
            }


            studentRegisterViewModel.Gender =
                Enum.GetNames(typeof(Gender)).Select(
                    x => new KeyValuePair<string, string>(x, x.ToString(CultureInfo.InvariantCulture)));
            studentRegisterViewModel.Interests = _interestService.GetAllInterests();
            return View(studentRegisterViewModel);
        }

当我尝试创建参与者时,出现以下错误。 {"无法将值 NULL 插入到列 'InterestName'、表 'StudyTourNetworkDB.dbo.Interests';列不允许空值。INSERT 失败。\r\n语句已终止。"}

理想情况下,根据我的想法,它应该在 Participants 表和 ParticipantsInterests 表中插入参与者信息。但它也试图在兴趣表中插入记录,这也不应该发生。请帮我解决这个问题。通过创建多对多关联,我可能做错了。

谢谢

4

1 回答 1

2
  • 从表中删除Id列并生成一个复合主键。将它们保留为外键。ParticipantInterestsParticipantIdInterestId

  • 将您的多对多映射更改为...

    //...
    HasMany(p => p.Interests).
    WithMany(i => i.Participants).
    //...
    

    ...并删除此映射线:

    modelBuilder.Entity<Participant>().HasRequired(p => p.Interests);
    
  • 将兴趣附加到上下文以避免 EF 尝试插入它:

    foreach (var interestItem in studentRegisterViewModel.SelectedInterests)
    {
        var interest = new Interest { Id = interestItem};
        context.Interests.Attach(interest);
        studentRegisterViewModel.Participant.Interests.Add(interest);
    }
    

    您必须将与上下文相关联的行带入您的服务类中。context我猜你的控制器中没有可用的。但希望你能明白。

于 2012-12-06T17:15:01.173 回答