5

如何翻转屏幕截图图像？我在其他任何地方都找不到我的问题。
示例代码：

/*
*@param fileLoc //Location of fileoutput destination
*@param format  //"png"
*@param WIDTH   //Display.width();
*@param HEIGHT  //Display.height();
*/
private void getScreenImage(){
             int[] pixels = new int[WIDTH * HEIGHT];
             int bindex;
             // allocate space for RBG pixels
             ByteBuffer fb = ByteBuffer.allocateDirect(WIDTH * HEIGHT * 3);//.order(ByteOrder.nativeOrder());
             // grab a copy of the current frame contents as RGB

             glReadPixels(0, 0, WIDTH, HEIGHT, GL_RGB, GL_UNSIGNED_BYTE, fb);

             BufferedImage image = new BufferedImage(WIDTH, HEIGHT,BufferedImage.TYPE_INT_RGB);
             // convert RGB data in ByteBuffer to integer array
             for (int i=0; i < pixels.length; i++) {
                 bindex = i * 3;
                 pixels[i] =
                     ((fb.get(bindex) << 16))  +
                     ((fb.get(bindex+1) << 8))  +
                     ((fb.get(bindex+2) << 0));
             }
             try {
                //Create a BufferedImage with the RGB pixels then save as PNG
                 image.setRGB(0, 0, WIDTH, HEIGHT, pixels, 0 , WIDTH);

                 ImageIO.write(image, format , fileLoc);
             }
             catch (Exception e) {
                 System.out.println("ScreenShot() exception: " +e);
             }
         }

基本上，该代码用于捕获屏幕并以“png”格式存储。
但它输出的是水平翻转的图像，因为glReadPixels();从
左下角到右上角读取。

那么如何在 I 之前水平翻转图像ImageIO.write();？

非常感谢，罗斯。

4

2 回答 2

8

EG 使用AffineTransform.

水平翻转图像

import java.awt.*;
import java.awt.geom.AffineTransform;
import java.awt.image.BufferedImage;
import javax.swing.*;

public class Test001 {

    public static BufferedImage getFlippedImage(BufferedImage bi) {
        BufferedImage flipped = new BufferedImage(
                bi.getWidth(),
                bi.getHeight(),
                bi.getType());
        AffineTransform tran = AffineTransform.getTranslateInstance(bi.getWidth(), 0);
        AffineTransform flip = AffineTransform.getScaleInstance(-1d, 1d);
        tran.concatenate(flip);

        Graphics2D g = flipped.createGraphics();
        g.setTransform(tran);
        g.drawImage(bi, 0, 0, null);
        g.dispose();

        return flipped;
    }

    Test001(BufferedImage bi) {
        JPanel gui = new JPanel(new GridLayout(1,2,2,2));

        gui.add(new JLabel(new ImageIcon(bi)));
        gui.add(new JLabel(new ImageIcon(getFlippedImage(bi))));

        JOptionPane.showMessageDialog(null, gui);
    }

    public static void main(String[] args) throws AWTException {
        final Robot robot = new Robot();
        Runnable r = new Runnable() {

            @Override
            public void run() {
                final BufferedImage bi = robot.createScreenCapture(
                        new Rectangle(0, 360, 200, 100));
                new Test001(bi);
            }
        };
        SwingUtilities.invokeLater(r);
    }
}
于 2012-12-07T03:10:49.597 回答
0

值得注意的是，简单地按照您想要的顺序从缓冲区中读取像素可能会更快，而不是向后读取它们并执行昂贵的转换操作。此外，由于您确定 BufferedImage 是TYPE_INT_RGB，因此直接写入其光栅应该是安全的。

ByteBuffer fb = BufferUtils.createByteBuffer(WIDTH * HEIGHT * 3);
BufferedImage image = new BufferedImage(WIDTH, HEIGHT, BufferedImage.TYPE_INT_RGB);
glReadPixels(0, 0, WIDTH, HEIGHT, GL_RGB, GL_UNSIGNED_BYTE, fb);
int[] pixels = ((DataBufferInt) image.getRaster().getDataBuffer()).getData();
for (int i = pixels.length - 1; i >= 0; i--) {
    int x = i % WIDTH, y = i / WIDTH * WIDTH;
    pixels[y + WIDTH - 1 - x] = (fb.get() & 0xff) << 16 | (fb.get() & 0xff) << 8 | fb.get() & 0xff;
}
于 2014-04-02T14:40:05.570 回答