java - Java中的多态排序转换

Question

我需要以下问题的帮助。首先我列出了 Numbers.java，下面是我对 Strings.java 的尝试。请帮忙！

1. 编写一个类似于 Numbers.java 的程序 Strings.java，它读入一个 String 对象数组并对它们进行排序。您可以只复制和编辑 Numbers.java。

   package hw05;
   
   /*  
   Demonstrates selectionSort on an array of integers.
   */ 
   
   import java.util.Scanner;
   
   
   public class Numbers {  
   // --------------------------------------------  
   // Reads in an array of integers, sorts them,  
   // then prints them in sorted order.  
   // --------------------------------------------  
   public static void main(String[] args) {
   
       Integer[] intList;
       int size;
   
       Scanner scan = new Scanner(System.in);
   
       System.out.print("\nHow many integers do you want to sort? ");
       size = scan.nextInt();
       intList = new Integer[size];
   
       System.out.println("\nEnter the numbers...");
       for (int i = 0; i < size; i++)
           intList[i] = scan.nextInt();
       Sorting.selectionSort(intList);
   
       System.out.println("\nYour numbers in sorted order...");
       for (int i = 0; i < size; i++)
           System.out.print(intList[i] + " ");
       System.out.println();
   
   }
   }
   

我的弦乐课

package hw05;

/*
Demonstrates selectionSort on an array of strings.
*/
import java.util.Scanner;

public class Strings {
    // --------------------------------------------
    // Reads in an array of strings, sorts them,
    // then prints them in sorted order.
    // --------------------------------------------
    public static void main(String[] args) {

        String[] stringList;
        String size;

        Scanner scan = new Scanner(System.in);

        System.out.print("\nHow many strings do you want to sort? ");
        size = scan.nextLine();
        stringList = new String[size];

        System.out.println("\nEnter the strings...");
        for (String i = 0; i < size; i++)
            stringList[i] = scan.nextLine();
        Sorting.selectionSort(stringList);

        System.out.println("\nYour strings in sorted order...");
        for (String i = 0; i < size; i++)
            System.out.print(stringList[i] + " ");
        System.out.println();

    }
}

Answer 1

由于这里的声明，您将收到一个错误：

String size;

当您稍后将其用作整数时：

stringList = new String[size];

你应该像这样使用 Integer.parse：

stringList = new String[Integer.parseInt(size)];

但是您稍后再次将 size 用于您的循环，因此我建议将其恢复为 int ，就像您在 Numbers.java 中一样。请务必将您的扫描仪改回：

scan.nextInt();

除此之外，我看不到任何其他问题。也许如果您发布输出并指出什么不起作用？