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我试图允许Listbox用户想要选择的项目中的橡皮筋或套索类型选择。我Listbox在一个网格中,我在网格中添加了一个控件,该控件在我要选择的区域上绘制一个矩形。我已经尝试测试这些Listbox项目以查看它们是否在矩形内,但它们似乎都返回它们没有。当查看VisualTreeHelper.GetDescendantBounds这些项目时(就像我对矩形所做的那样,得到它的 X,Y)它总是将 X,Y 返回为每个项目的 0,0。我在命中测试方面做错了什么?

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1 回答 1

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您可以使用此代码来获取 UIElements 相对于另一个 UIElement 的位置和边界。代码取自这篇文章

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;

public static class UIHelper
{
    public static Boolean GetUIElementCornersRelativTo(UIElement Base,
                                                UIElement RelativeTo,
                                                ref Point TopLeft,
                                                ref Point BottomLeft,
                                                ref Point BottomRight,
                                                ref Point TopRight,
                                                ref String Message)
    {
        try
        {
            if (Base == null)
            {
                throw new Exception("Base UIElement is null");
            }
            if (RelativeTo == null)
            {
                throw new Exception("RelativTo UIElement is null");
            }

            TopLeft = Base.TranslatePoint(new Point(0, 0), RelativeTo);
            BottomLeft = Base.TranslatePoint(new Point(0, Base.RenderSize.Height), RelativeTo);
            BottomRight = Base.TranslatePoint(new Point(Base.RenderSize.Width, Base.RenderSize.Height), RelativeTo);
            TopRight = Base.TranslatePoint(new Point(Base.RenderSize.Width, 0), RelativeTo);

            Message = "OK";
            return true;
        }
        catch (Exception ex)
        {
            Message = ex.Message;
            return false;
        }
    }
    public static Boolean GetPointRelativTo(UIElement Base,
                                     UIElement RelativeTo,
                                     Point ToProjectPoint,
                                     ref Point Result,
                                     ref String Message)
    {
        try
        {
            if (Base == null)
            {
                throw new Exception("Base UIElement is null");
            }
            if (RelativeTo == null)
            {
                throw new Exception("RelativTo UIElement is null");
            }

            if (ToProjectPoint == null)
            {
                throw new Exception("To project point is null");
            }

            Result = Base.TranslatePoint(ToProjectPoint, RelativeTo);

            Message = "OK";
            return true;
        }
        catch (Exception ex)
        {
            Message = ex.Message;
            return false;
        }
    }
}
于 2009-09-17T13:32:09.323 回答