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我有一个名为的表applications和一个名为 的表application_history。我想保留应用程序的历史记录，并且想到每当applications表中的行更新时使用触发器将该行复制到application_history实际更新之前。

目前，我已经从另一个 SO 帖子中写出了这段代码：

create or replace 
trigger APPLICATION_UPDATE_TRG
BEFORE UPDATE ON TBL_APPLICATIONS 
FOR EACH ROW
DECLARE
  CURSOR curAppHistory IS
    SELECT record_number, job_id, submitted_date, status_id, id
      FROM tbl_application
      WHERE id = :old.id;
  vRowAppHistory curAppHistory%ROWTYPE;
BEGIN
  OPEN curAppHistory;
  FETCH curAppHistory INTO vRowAppHistory;
  CLOSE curAppHistory;
  INSERT INTO tbl_application_history
  (record_number, job_id, submitted_date, status_id, application_id)
  VALUES (vRowAppHistory.record_number, vRowAppHistory.job_id, vRowAppHistory.submitted_date, 
  vRowAppHistory.status_id, vRowAppHistory.id);
END;

但是，它没有正确编译。SQL Developer 抛出 3 个关于命令未正确结束和语句被忽略的错误。

这样做的正确方法是什么？

编辑：错误：

Error(2,10): PLS-00341: declaration of cursor 'CURAPPHISTORY' is incomplete or malformed
Error(3,5): PL/SQL: SQL Statement ignored
Error(4,12): PL/SQL: ORA-00942: table or view does not exist
Error(6,18): PL/SQL: Item ignored
Error(9,3): PL/SQL: SQL Statement ignored
Error(9,28): PLS-00320: the declaration of the type of this expression is incomplete or malformed
Error(11,3): PL/SQL: SQL Statement ignored
Error(14,29): PLS-00320: the declaration of the type of this expression is incomplete or malformed
Error(14,44): PL/SQL: ORA-00984: column not allowed here
4

1 回答 1

2

Error(4,12): PL/SQL: ORA-00942: table or view does not exist

错字？您在此处指定了两个不同的表。

BEFORE UPDATE ON TBL_APPLICATIONS

FROM tbl_application

无论如何，你会得到ORA-04091这个触发器。类似的测试用例：

SYSTEM@dwal> create table t (key number primary key, value varchar2(10));

Table created.

SYSTEM@dwal> insert into t values (1, 'abcdef');

1 row created.

SYSTEM@dwal> insert into t values (2, 'ghijkl');

1 row created.

SYSTEM@dwal> commit;

Commit complete

SYSTEM@dwal> ed
Wrote file S:\\tools\buffer.sql

  1  create or replace trigger tt
  2  before update on t for each row
  3  declare
  4  cursor c is
  5    select key, value
  6      from t
  7     where key = :old.key;
  8  v c%rowtype;
  9  begin
 10    open c;
 11    fetch c into v;
 12    close c;
 13    dbms_output.put_line(v.value);
 14* end;
09:58:51 SYSTEM@dwal> /

Trigger created.


SYSTEM@dwal> update t set value = '123';
update t set value = '123'
       *
ERROR at line 1:
ORA-04091: table SYSTEM.T is mutating, trigger/function may not see it
ORA-06512: at "SYSTEM.TT", line 3
ORA-06512: at "SYSTEM.TT", line 8
ORA-04088: error during execution of trigger 'SYSTEM.TT'

你可能应该这样做：

INSERT INTO tbl_application_history 
(record_number, job_id, submitted_date, status_id, application_id)
VALUES 
(:old.record_number, :old.job_id, :old.submitted_date, :old.status_id, :old.id);

在这种情况下，整个触发器将是一个插入语句：

SYSTEM@dwal> create table t_log (key number, value varchar2(10));

Table created.

SYSTEM@dwal> ed
Wrote file S:\\tools\buffer.sql

  1  create or replace trigger tt
  2  before update on t for each row
  3  begin
  4    insert into t_log values (:old.key, :old.value);
  5* end;
SYSTEM@dwal> /

Trigger created.

SYSTEM@dwal> update t set value = '123';

2 rows updated.

SYSTEM@dwal> commit;

Commit complete.

SYSTEM@dwal> select * from t_log;

       KEY VALUE
---------- ----------
         1 abcdef
         2 ghijkl


SYSTEM@dwal> select * from t;

       KEY VALUE
---------- ----------
         1 123
         2 123
于 2012-12-06T01:55:42.293 回答