windows - 在表中查找字符串并返回值

Question

想象一下这个.txt文件：

Example.txt

Row    Column1    Column2    Column3 <br>
1       aaa         bbb        ccc<br>
2       ddd         eee        fff

如何使用命令行获取表中的值？

前任。: (Row=2, Column2) 返回值“eee”。
前任。: (Row=1, Column3) 返回值“ccc”。

我正在尝试findstr，但我不知道如何实现它。

Answer 1

假设行信息实际上在文件中，并假设没有值包含空格：

@echo off
call :getValue  2  Column2  "Example.txt"
call :getValue  1  Column3  "Example.txt"
call :getValue  0  Column1  "Example.txt"
call :getValue  1  DoesNotExist  "Example.txt"
exit /b

:getValue
setlocal
<%3 set /p "header="
set token=0
for %%C in (%header%) do (
  set /a token+=1
  if %%C==%2 goto columnFound
)
echo Column %2 not found in %3
exit /b

:columnFound
for /f "tokens=%token%" %%A in ('findstr /blc:"%1 " %3') do (
  echo %3 (Row=%1, %2^) = %%A
  exit /b
)
echo Row %1 not found in %3
exit /b

结果

"Example.txt" (Row=2, Column2) = eee
"Example.txt" (Row=1, Column3) = ccc
Row 0 not found in "Example.txt"
Column DoesNotExist not found in "Example.txt"