28

从 GetResponseStream 读取 HTTP 响应的最佳方法是什么？

目前我正在使用以下方法。

Using SReader As StreamReader = New StreamReader(HttpRes.GetResponseStream)
   SourceCode = SReader.ReadToEnd()
End Using

我不太确定这是否是读取 http 响应的最有效方式。

我需要将输出作为字符串，我看过一篇采用不同方法的文章，但我不太确定它是否是一个好文章。在我的测试中，这些代码在不同的网站上存在一些编码问题。

您如何阅读网络回复？

4

6 回答 6

19

我对字符串执行此操作的简单方法。注意构造函数的true第二个参数StreamReader。这告诉它从字节顺序标记中检测编码，并且可能有助于解决您遇到的编码问题。

string target = string.Empty;
HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create("http://www.informit.com/guides/content.aspx?g=dotnet&seqNum=583");

HttpWebResponse response = (HttpWebResponse)httpWebRequest.GetResponse();
try
{
  StreamReader streamReader = new StreamReader(response.GetResponseStream(),true);                
  try
  {
    target = streamReader.ReadToEnd();
  }
  finally
  {
    streamReader.Close();
  }
}
finally
{
  response.Close();
}
于 2010-05-31T17:48:33.317 回答
18

我使用这样的东西从 URL 下载文件：

if (!Directory.Exists(localFolder))
{
    Directory.CreateDirectory(localFolder);   
}


try
{
    HttpWebRequest httpRequest = (HttpWebRequest)WebRequest.Create(Path.Combine(uri, filename));
    httpRequest.Method = "GET";

    // if the URI doesn't exist, an exception will be thrown here...
    using (HttpWebResponse httpResponse = (HttpWebResponse)httpRequest.GetResponse())
    {
        using (Stream responseStream = httpResponse.GetResponseStream())
        {
            using (FileStream localFileStream = 
                new FileStream(Path.Combine(localFolder, filename), FileMode.Create))
            {
                var buffer = new byte[4096];
                long totalBytesRead = 0;
                int bytesRead;

                while ((bytesRead = responseStream.Read(buffer, 0, buffer.Length)) > 0)
                {
                    totalBytesRead += bytesRead;
                    localFileStream.Write(buffer, 0, bytesRead);
                }
            }
        }
    }
}
catch (Exception ex)
{
    // You might want to handle some specific errors : Just pass on up for now...
    // Remove this catch if you don't want to handle errors here.
    throw;
}
于 2008-09-26T01:43:45.763 回答
14

也许您可以查看WebClient类。这是一个例子：

using System.Net;

namespace WebClientExample
{
    class Program
    {
        static void Main(string[] args)
        {
            var remoteUri = "http://www.contoso.com/library/homepage/images/";
            var fileName = "ms-banner.gif";
            WebClient myWebClient = new WebClient();
            myWebClient.DownloadFile(remoteUri + fileName, fileName);
        }
    }
}
于 2009-05-10T21:50:49.600 回答
7

在powershell中，我有这个功能：

function GetWebPage
{param ($Url, $Outfile)
    $request = [System.Net.HttpWebRequest]::Create($SearchBoxBuilderURL)
    $request.AuthenticationLevel = "None"
    $request.TimeOut = 600000     #10 mins 
    $response = $request.GetResponse() #Appending "|Out-Host" anulls the variable
    Write-Host "Response Status Code: "$response.StatusCode
    Write-Host "Response Status Description: "$response.StatusDescription
    $requestStream = $response.GetResponseStream()
    $readStream = new-object System.IO.StreamReader $requestStream
    new-variable db | Out-Host
    $db = $readStream.ReadToEnd()
    $readStream.Close()
    $response.Close()
    #Create a new file and write the web output to a file
    $sw = new-object system.IO.StreamWriter($Outfile)
    $sw.writeline($db) | Out-Host
    $sw.close() | Out-Host
}

我这样称呼它：

$SearchBoxBuilderURL = $SiteUrl + "nin_searchbox/DailySearchBoxBuilder.asp"
$SearchBoxBuilderOutput="D:\ecom\tmp\ss2.txt"
GetWebPage $SearchBoxBuilderURL $SearchBoxBuilderOutput
于 2012-05-10T06:52:16.250 回答
3

You forgot to define "buffer" and "totalBytesRead":

using ( FileStream localFileStream = ....  
{  
    byte[] buffer = new byte[ 255 ];  
    int bytesRead;  
    double totalBytesRead = 0;  

    while ((bytesRead = ....
于 2008-10-02T10:10:04.037 回答
1

我遇到了类似的情况：

我试图使用 BasicHTTPBinding 在使用 SOAP 服务的 HTTP 错误的情况下读取原始响应。

但是，当使用 读取响应时GetResponseStream()，出现错误：

流不可读

所以，这段代码对我有用：

try
{
    response = basicHTTPBindingClient.CallOperation(request);
}
catch (ProtocolException exception)
{
    var webException = exception.InnerException as WebException;

    var alreadyClosedStream = webException.Response.GetResponseStream() as MemoryStream;
    using (var brandNewStream = new MemoryStream(alreadyClosedStream.ToArray()))
    using (var reader = new StreamReader(brandNewStream))
        rawResponse = reader.ReadToEnd();
}
于 2017-05-15T14:14:50.257 回答