我正在 Android Google maps v2 中进行地图聚类。我只想将标记从一个地理点动画到另一个地理点。有没有办法在谷歌地图 v2 中移动标记？
问问题
71270 次
5 回答
56
在 google map v2演示应用程序中有一个移动标记的示例 .. 在 play 库的示例中！！
我已经调查过了！！这里是移动标记的代码：->
public void animateMarker(final Marker marker, final LatLng toPosition,
final boolean hideMarker) {
final Handler handler = new Handler();
final long start = SystemClock.uptimeMillis();
Projection proj = mGoogleMapObject.getProjection();
Point startPoint = proj.toScreenLocation(marker.getPosition());
final LatLng startLatLng = proj.fromScreenLocation(startPoint);
final long duration = 500;
final Interpolator interpolator = new LinearInterpolator();
handler.post(new Runnable() {
@Override
public void run() {
long elapsed = SystemClock.uptimeMillis() - start;
float t = interpolator.getInterpolation((float) elapsed
/ duration);
double lng = t * toPosition.longitude + (1 - t)
* startLatLng.longitude;
double lat = t * toPosition.latitude + (1 - t)
* startLatLng.latitude;
marker.setPosition(new LatLng(lat, lng));
if (t < 1.0) {
// Post again 16ms later.
handler.postDelayed(this, 16);
} else {
if (hideMarker) {
marker.setVisible(false);
} else {
marker.setVisible(true);
}
}
}
});
}
希望对大家有帮助！！
于 2012-12-17T10:08:35.220 回答
10
使用 ValueAnimator 的正确方法：
double[] startValues = new double[]{marker.getPosition().latitude, marker.getPosition().longitude};
double[] endValues = new double[]{destLatLng.latitude, destLatLng.longitude};
ValueAnimator latLngAnimator = ValueAnimator.ofObject(new DoubleArrayEvaluator(), startValues, endValues);
latLngAnimator.setDuration(600);
latLngAnimator.setInterpolator(new DecelerateInterpolator());
latLngAnimator.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
@Override
public void onAnimationUpdate(ValueAnimator animation) {
double[] animatedValue = (double[]) animation.getAnimatedValue();
marker.setPosition(new LatLng(animatedValue[0], animatedValue[1]));
}
});
latLngAnimator.start();
DoubleArrayEvaluator包中不存在android.animation，有我的实现：
import android.animation.TypeEvaluator;
/**
* Inspired from {@link android.animation.FloatArrayEvaluator}
* <p/>
* This evaluator can be used to perform type interpolation between <code>double[]</code> values.
* Each index into the array is treated as a separate value to interpolate. For example,
* evaluating <code>{100, 200}</code> and <code>{300, 400}</code> will interpolate the value at
* the first index between 100 and 300 and the value at the second index value between 200 and 400.
*/
public class DoubleArrayEvaluator implements TypeEvaluator<double[]> {
private double[] mArray;
/**
* Create a DoubleArrayEvaluator that does not reuse the animated value. Care must be taken
* when using this option because on every evaluation a new <code>double[]</code> will be
* allocated.
*
* @see #DoubleArrayEvaluator(double[])
*/
public DoubleArrayEvaluator() {
}
/**
* Create a DoubleArrayEvaluator that reuses <code>reuseArray</code> for every evaluate() call.
* Caution must be taken to ensure that the value returned from
* {@link android.animation.ValueAnimator#getAnimatedValue()} is not cached, modified, or
* used across threads. The value will be modified on each <code>evaluate()</code> call.
*
* @param reuseArray The array to modify and return from <code>evaluate</code>.
*/
public DoubleArrayEvaluator(double[] reuseArray) {
mArray = reuseArray;
}
/**
* Interpolates the value at each index by the fraction. If
* {@link #DoubleArrayEvaluator(double[])} was used to construct this object,
* <code>reuseArray</code> will be returned, otherwise a new <code>double[]</code>
* will be returned.
*
* @param fraction The fraction from the starting to the ending values
* @param startValue The start value.
* @param endValue The end value.
* @return A <code>double[]</code> where each element is an interpolation between
* the same index in startValue and endValue.
*/
@Override
public double[] evaluate(float fraction, double[] startValue, double[] endValue) {
double[] array = mArray;
if (array == null) {
array = new double[startValue.length];
}
for (int i = 0; i < array.length; i++) {
double start = startValue[i];
double end = endValue[i];
array[i] = start + (fraction * (end - start));
}
return array;
}
}
于 2016-02-04T15:34:49.247 回答
6
我是这样做的：
private Marker marker;
在谷歌地图上添加 标记时：
if(marker!=null){
marker.remove();
}
LatLng mLatLng = new LatLng(Your_Latitude, Your_Longitude);
marker = mMapHistory.addMarker(new MarkerOptions().position(mLatLng).title("My Title").snippet("My Snippet").icon(BitmapDescriptorFactory.fromResource(R.mipmap.ic_launcher)));
希望这种最简单的方法对您有所帮助。
于 2015-07-25T15:49:58.957 回答
4
请试试这个：
private static void addMarkerWithCameraZooming(Context ctx, GoogleMap googleMap, double latitude, double longitude, String title, boolean dragabble) {
LatLng current_latlng = new LatLng(latitude, longitude);
googleMap.addMarker(new MarkerOptions().position(current_latlng)
.title(title)
.snippet(getLocality(current_latlng, ctx))
.icon(BitmapDescriptorFactory.fromResource(R.drawable.person_marker))
.draggable(dragabble)
);
CameraPosition cameraPosition = new CameraPosition.Builder().target(new LatLng(latitude, longitude)).zoom(12).tilt(30).build();
googleMap.animateCamera(CameraUpdateFactory.newCameraPosition(cameraPosition));
}
mGoogleMap.setOnMarkerDragListener(new OnMarkerDragListener() {
@Override
public void onMarkerDragStart(Marker markerDragStart) {
// TODO Auto-generated method stub
if (BuildConfig.DEBUG)
Log.i("Marker drag", "start");
}
@Override
public void onMarkerDragEnd(Marker markerDragEnd) {
if (BuildConfig.DEBUG)
Log.i("Marker drag", "start");
}
@Override
public void onMarkerDrag(Marker markerDrag) {
if (BuildConfig.DEBUG)
Log.i("Marker drag", "start");
}
});
于 2014-07-04T13:15:36.693 回答
1
嗨，我遇到了同样的问题，这是我的帖子Google Maps Android api v2 和当前位置
您可以使用 Marker 的 remove() 方法用新标记删除旧标记。我希望这是你需要的
于 2012-12-12T18:39:49.317 回答