ruby - Ruby 中的正则表达式字符串解析

Question

我有这个集合（点数可变，这里是 2）：

A 
 This is some Text belonging to A
 This also belongs to A
B 
 This should be with B
 same with this
...
...

我希望它最终成为这样的字符串：

A This is some Text belonging to A This also belongs to A
B This should be with B same with this

我的尝试是这样的：

answer.scan(/^([A-Z].+?(?=^[A-Z]))/m).map { |d| d.delete("\n") }.join("\n")

问题是这与最后一组不匹配（您可以假设字符串以最后一组结尾）有什么想法吗？:)

编辑1：修复了一个复制错误并在Rubular中尝试了一个新的正则表达式，哪种方法有效，但仍有一些不必要的匹配？

Answer 1

text = <<EOS
A 
 This is some Text belonging to A
 This also belongs to A
B 
 This should be with B
 same with this
 variable line
EOS

text.gsub(/\s?\n\s/, ' ')

# Outputs: 
# A This is some Text belonging to A This also belongs to A
# B This should be with B same with this variable line

Answer 2

answer = answer
.scan(/^([A-Z].+?(?=^[A-Z]))|(^[A-Z].+?\Z)/m)
.map {|item| item.reject { |i| i.nil? } }
.map { |d| d[0].delete("\n") }
.join("\n")

似乎现在可以工作......虽然可能不是最好的方法