1

在这段代码中,我加载了一些骰子的图像,并尝试在表格中显示其中的一些。我不确定我是否正确构建了数组,但这是我发现的使用图像传播数组的示例之一。

<table id="dicebox">
                <tr>
                    <td id="d1"></td>
                    <td id="d2"></td>
                    <td id="d3"></td>
                    <td id="d4"></td>
                    <td id="d5"></td>
                </tr>
            </table>
<script>

            var diceB = new Array(7);
            //Blue dice
            var diceP = new Array(7);
            //Purple dice
            var diceValue = new Array(0, 1, 2, 3, 4, 5, 6);

            //initializing blue dice array
            diceB[0] = new Image(50, 50);
            diceB[0].src = "images/dice0B.gif"
            diceB[1] = new Image(50, 50);
            diceB[1].src = "images/dice1B.gif"
            diceB[2] = new Image(50, 50);
            diceB[2].src = "images/dice2B.gif"
            diceB[3] = new Image(50, 50);
            diceB[3].src = "images/dice3B.gif"
            diceB[4] = new Image(50, 50);
            diceB[4].src = "images/dice4B.gif"
            diceB[5] = new Image(50, 50);
            diceB[5].src = "images/dice5B.gif"
            diceB[6] = new Image(50, 50);
            diceB[6].src = "images/dice6B.gif"


            for(var i = 1; i < 6; i++) {
                document.getElementById('d' + i).innerHTML = diceB[i].src;
4

2 回答 2

1

如何使用appendChild

for(var i = 1; i < 6; i++) {
    document.getElementById('d' + i).appendChild(diceB[i]);
于 2012-12-04T21:38:28.860 回答
1

您没有编写图像标签,您必须执行以下操作:

for(var i = 1; i < 6; i++) {
                document.getElementById('d' + i).innerHTML = '<img src="'+diceB[i].src+'" />';

}
于 2012-12-04T21:40:54.040 回答