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以下脚本旨在获取动态生成的 SQL 语句，然后运行它。该脚本将运行，但它不会返回预期的结果，而是返回动态 SQL 字符串的文本。产生的字符串是我需要运行的字符串，但它被调用了32次（奇怪的数字，我不知道为什么会这样）。有谁明白为什么这不仅仅是返回动态生成的 SQL 语句的结果集？SQL Server 2008 R2

作为记录，SQL Server 将查询解释为 32 条不同的选择语句，每条语句都在自己的行中。

返回的字符串

SELECT DISTINCT x.patid 
FROM   (SELECT ic.patid 
        FROM   icdclm AS ic 
        WHERE  ic.icd LIKE '123%') AS x1 
       INNER JOIN (SELECT ic.patid 
                   FROM   icdclm AS ic 
                   WHERE  ic.icd LIKE '456%') x2 
               ON x2.patid = x1.patid 
       INNER JOIN (SELECT ic.patid 
                   FROM   icdclm AS ic 
                   WHERE  ic.icd LIKE '456%') x3 
               ON x3.patid = x1.patid 
       INNER JOIN (SELECT ic.patid 
                   FROM   icdclm AS ic 
                   WHERE  ic.icd LIKE '456%') x4 
               ON x4.patid = x1.patid 
       INNER JOIN (SELECT ic.patid 
                   FROM   icdclm AS ic 
                   WHERE  ic.icd LIKE '456%') x5 
               ON x5.patid = x1.patid

我的代码生成上述字符串而不是执行该 SQL：

ALTER PROC Getmultiplecomorbidquery (@sqlquery NVARCHAR(1000) output) 
AS 
    DECLARE @x   INT, 
            @y   INT, 
            @sql NVARCHAR(1000) 

    SELECT @x = 1, 
           @y = 5, 
           @sql = 'select distinct x.patid from ( select ic.patid from icdClm as ic where ic.icd like ''123%'' ) as  x' + Cast(@x AS CHAR(1)) 

    WHILE @x < @y 
      BEGIN; 
          SET @sql=@sql + '  inner join  ( select ic.patid from icdClm as ic where ic.icd like ''456%'' ) x' + Cast(@x+1 AS CHAR(1)) + ' on x' 
                   + Cast(@x+1 AS CHAR(1)) 
                   + '.patid=x1.patid' 
          SET @x=@x + 1 
      END; 

    SET @sqlquery = @sql 

    SELECT @sql 
code i used to call
    DECLARE @sqlquery NVARCHAR(1000) 

    SET @sqlquery='' 

    EXECUTE dbo.Getmultiplecomorbidquery 
      @sqlquery output 

    SELECT @sqlquery
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1 回答 1

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你永远不会执行查询，只是返回它，你需要一个 EXECUTE @sql 在那里（或执行结果）。

于 2012-12-04T21:27:22.813 回答