3

我正在尝试将字符输入到链表中，其中字符可以是“A”、“a”、“G”、“g”、“T”、“t”、“C”或“c”。

我还不熟悉C，我知道我在这里搞砸了一些东西：

do{
  printf ("\nEnter a new nucleotide: \n");
  scanf("%c",&newChar);
          /* Checking */
  if(newChar == 'A' ||
     newChar == 'a' || 
     newChar == 'G' || 
     newChar == 'g' || 
     newChar == 'T' || 
     newChar == 't' || 
     newChar == 'C' || 
     newChar == 'c' )
  {
    AddToSequence(newChar);
    size++;
  } else {
    printf ("\nBad Element");
  }
}while(newChar != 'x');

newChar 用垃圾值初始化，在本例中为“q”。

输入“x”退出循环，输入任何可接受的值调用 AddToSequence()，任何不可接受的值都会收到警告。

由于某种原因，无论 newChar 中的值是什么，它都会跳转到 else。它还将直接跳过 scanf 而不等待用户输入，并且每次循环时执行两个循环。谁能告诉我哪里出错了？

完整程序：

#include<stdio.h>
#include<stdlib.h>

/*Structure declaration for the node*/
struct node{
   char nucleotide;
   struct node *point;
}*start;

/* Adds a nucleotide to the chain. Creates a new linked list if no chain exists exists.*/
void AddToSequence(char nucleotide){
  struct node *loc, *first;
  //Dynamic memory is been allocated for a node
  first=(struct node*)malloc(sizeof(struct node));
  first->nucleotide=nucleotide;
  first->point=NULL;
  if(start==NULL){
    /*If list is empty*/
    start=first;
  }else{
    /*Element inserted at the end*/
    loc=start;
    while(loc->point!=NULL){
      loc=loc->point;
      loc->point=first;
    }
  }
}

/* Display elements */
void Display(){
  struct node *loc;
  if(start == NULL){
    printf ("\n\nList is empty");
    return;
  }
  loc=start;
  printf("\n\nList is : ");
  while(loc!=NULL){
    printf ("%c", loc->nucleotide);
    loc=loc->point;
  }
  printf ("\n");
}

/* Finds and displays percentage of the chain made up of each nucleotide. */
void Percentage(int size){
  struct node *loc;
  if(start == NULL){
    printf ("\n\nList is empty");
    return;
  }
  loc=start;
  printf("\n\nList is : ");
  int A = 0, G =0, T =0, C = 0;
  double Adouble = 0, Gdouble =0, Tdouble=0, Cdouble=0;
  while(loc!=NULL){
    if(loc->nucleotide=='A' || 'a'){A++;}
    if(loc->nucleotide=='G' || 'g'){G++;}
    if(loc->nucleotide=='T' || 't'){T++;}
    if(loc->nucleotide=='C' || 'c'){C++;}    
    loc=loc->point;   
  }
  printf ("\n"); 

  /* Convert to double for percentages as int loses precision */
  Adouble =A;
  Gdouble =G;
  Tdouble =T;
  Cdouble =C; 
  Adouble =(Adouble/size)*100;
  Gdouble =(Gdouble/size)*100;
  Tdouble =(Tdouble/size)*100;
  Cdouble =(Cdouble/size)*100; 
  printf("\nA: %f", Adouble);
  printf("\nG: %f", Gdouble);
  printf("\nT: %f", Tdouble);
  printf("\nC: %f", Cdouble); 
}

/* There be dragons beyond here */
int main(){
  int navigate, size =0;
  char newChar = 'q';
  do{ /* Menu */
    printf("\n 1. Create / Extend Sequence\n");
    printf("\n 2. Display Sequence\n");
    printf("\n 3. Count \n");
    printf("\n 0. Exit \n");
    printf("\nPlease select an option (0 to 3)\n");
    scanf("%d",&navigate);  
    switch (navigate){
      case 0: /* Exit */
        break;
      case 1: /* Add nucleotides */
        do{
          printf ("\nEnter a new nucleotide: \n");
          scanf("%c",&newChar);
          /* Some error checking */
          if(newChar == 'A' || newChar == 'a' || newChar == 'G' || newChar == 'g' || newChar == 'T' || newChar == 't' || newChar == 'C' || newChar == 'c' ){
            AddToSequence(newChar);
            size++;
          } else {
            printf ("\nBad Element");
          }
        }while(newChar != 'x');
        break;
      case 2:
        Display();
        break;
      case 3:
        Percentage(size);
        break;
      default:
        printf ("\n\nBad choice. Please select another.\n");
    }
  } while (navigate !=0); 
  return 0 ;
}
4

4 回答 4

13

你不处理换行符。说明%c符不会跳过空格。尝试：

scanf(" %c", &newChar);
    /* ^ <-- Makes `scanf` eat the newline. */

或者也许添加一个明确的测试。

scanf(...);
if (newChar == '\n')
    continue;
于 2012-12-04T19:59:24.943 回答
6

添加空间以"%c"捕捉换行符。空格字符用于捕捉空格字符、制表符、换行符

scanf("%c ",&newChar);
于 2012-12-04T20:00:35.483 回答
4

你要离开'\n'on stdin：

scanf("%d",&navigate);  
getchar(); // consume the newline character
...
scanf("%c",&newChar);
getchar(); // consume the newline character

或者由于您已经在使用scanf()，您可以告诉 scanf 本身来处理换行符：

scanf("%d\n", &navigate);
....
scanf("%c\n",&newChar);

更好的是，您可以通过在格式说明符后添加一个空格来使其保持打开状态：

scanf("%d ", &navigate);
....
scanf("%c ",&newChar);

以防万一用户想要执行以下操作：2<tab key><enter key>

不管你如何处理它，关键是你需要使用换行符。

于 2012-12-04T20:00:09.227 回答
0

利用

newChar=getche();

这是一个非标准函数，它从键盘获取字符，回显到屏幕。

于 2017-10-20T18:29:30.543 回答