c - FOR 循环时出现分段错误（核心转储）

Question

这是C上的代码：

这是功能：

#include <stdio.h>
#include <stdlib.h>

struct worker
{
    char firstName;
    char lastName;
    char middleName;
    int age;
    float height;
};

void enterData();
void displayData();
void makeCalc();

struct worker *b;
int count;

int main(void)
{
    enterData();
    displayData();
    makeCalc();
    free(b);
    return 0;
}

void enterData()
{
    char firstName;
    char lastName;
    char middleName;
    int age;
    float height;


    printf("Количество работников: \n");
    scanf("%d", &count);

    if(count <= 0){
        exit(0);
    }

    b = (struct worker *)malloc(count*sizeof(struct worker));


    for(int i = 0; i<count; i++){
        printf("Введите имя, фамилию, отчестве, возраст и рост через пробел: \n");
        scanf("%s%s%s%d%f", &firstName, &lastName, &middleName, &age, &height);
        struct worker a = (struct worker) {firstName, lastName, middleName, age, height};
        b[i] = a;
    }

}

如果显示程序，则在这部分运行时Segmentation fault (core dumped)：

for(int i = 0; i<count; i++){
            printf("Enter name, surname and middle name: \n");
            scanf("%s%s%s%d%f", &firstName, &lastName, &middleName, &age, &height);
            struct worker a = (struct worker) {firstName, lastName, middleName, age, height};
            b[i] = a;

这可能是什么原因？我是 C 新手；

PS 我在 ubuntu 12.04 上使用 GCC 编译器。和通用的文本编辑器。

Answer 1

有你的问题：

    scanf("%s%s%s%d%f", &firstName, &lastName, &middleName, &age, &height);

您扫描字符串，但您的变量只是字符：

   char firstName;
   char lastName;
   char middleName;

Answer 2

我想你可能想为你的数据提供一个缓冲区：

char firstName[SOME_BIG_ENOUGH_SIZE];

而不是单个字符：

char firstName;

Answer 3

问题是您在声明中使用 char 类型并%s在 scanf中使用

必须更改这些以保持字符串

 char firstName;
 char lastName;
 char middleName;

应该改为

char firstName[MAX]; //where MAX is any convenient high value.
char lastName[MAX];
char middleName[MAX];