1

如何使用 YIi 查询生成器构建此查询

SELECT First_Name,User_ID,
FROM `Users`
WHERE First_name LIKE $_GET['name']
4

2 回答 2

6

正如 Örs 所说,一切都在Yii 指南中!

$user = Yii::app()->db->createCommand()
    ->select('First_Name, User_ID')
    ->from('Users')
    ->where('First_name like :name', array(':name'=>$_GET['name']))
    ->queryRow();
于 2012-12-04T13:39:22.447 回答
0
$cr = new CDbCriteria();
$cr->condition = "First_name LIKE '%:name%'";
$cr->params = array(':name'=>$_GET['name']);

$users = Users::model()->findAll($cr);

其他方式

于 2015-05-09T10:52:36.980 回答