嗨,我正在编写一个脚本供用户输入 url。我应该验证 url 并让用户知道 url 是否有效。如果我故意输入错误的 url,我会收到 gaierror 的错误消息,但我已经输入了错误在这里处理代码,以便我的程序收到一条消息“无法连接”,就像正常退出一样。看起来像代码行“如果 sock 是 None:-print 'could not open socket' 没有在下面的程序中执行。我是新来的在套接字编程中。我想我做错了什么。有人可以在这里帮助我。在此先感谢!
#!/usr/bin/env python
import socket
import sys
def hello(c):
t=c
port = 80
slash=t.split("/")
basename="/".join(slash[2:3])
pathname="/"+"/".join(slash[3:])
sock=None
for res in socket.getaddrinfo(basename, port, socket.AF_UNSPEC, socket.SOCK_STREAM):
af, socktype, proto, canonname, sa = res
try:
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
except socket.error:
sock= None
continue
try:
sock.connect((basename, port))
except socket.error:
sock= None
continue
if sock is None:
print 'could not open socket'###I dont get this printed
sys.exit(0)
sock.send("HEAD %s HTTP/1.0\r\n\r\n" % pathname)
l=sock.recv(12)
return l
sys.exit(1)
sock.close()
``I call the hello function from here``
k= hello("https://mail.yah")`purposefully wrong to verify error handle
print k
newsplit=k.split()
print newsplit
insplit=eval(newsplit[1])
print insplit
if insplit==404:
print "bad"
else:
print "ok"
我收到以下错误消息:
Traceback (most recent call last):
File "C:/myserver/cgi-bin/domain.py", line 40, in <module>
k= hello("https://mail.yah")
"C:/myserver/cgi-bin/domain.py", line 13, in hello
for res in socket.getaddrinfo(basename, port, socket.AF_UNSPEC, socket.SOCK_STREAM):
gaierror: [Errno 11004] getaddrinfo failed